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olganol [36]
3 years ago
10

Linda is playing a game where she is trying to draw a diamond from a standard deck of cards. If she doesn't get a diamond, she r

eplaces the card, shuffles the deck, and tries again. If she draws a card 4 times and doesn't get
a diamond, she loses. What is the probability that Linda loses the game? Round your answer to the nearest tenth of a percent.
Mathematics
2 answers:
atroni [7]3 years ago
7 0

Answer:

The answer would be 0.2%

Step-by-step explanation:

There's 52 cards in a standard deck of cards and a set of 4 for each different symbol. 100% of the deck would be 52 cards and each deck has 4 suits and each suite has 13 cards and 75% of the cards aren't the diamond Linda is looking for so it would be a slim to none chance on pulling a diamond out of the deck and shuffling the deck each time makes it worse so it gives her like a 0.2% chance of pulling a diamond.

Hope this helps :))

Airida [17]3 years ago
3 0

Answer: 31.6%

Step-by-step explanation:

A P E X

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2 years ago
Is my answer right? if not break the hard news and give me the right one​
mafiozo [28]

Answer:

yeah

Step-by-step explanation:

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6 0
2 years ago
Simplify 3^2 x 3^3 <br><br> A. 3<br><br> B. 3^6<br><br> C. 3^5<br><br> D. 3^8
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5 0
3 years ago
Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require
kotegsom [21]

Answer:

4

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = 3\frac{2}{3} yards

Number of yards required make one ribbon = \frac{2}{3} yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

a\dfrac{b}{c} = \dfrac{a\times c+b}{c}

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}

One hair bow requires \frac{2}{3} yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4

4 hair bows can be made.

4 0
2 years ago
Unpopular opinion
Harlamova29_29 [7]

Answer:

no i think you are just unlucky :)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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