<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
4
Step-by-step explanation:
It's easy because 4-4=0 and anything divided by zero is zero.
6x=-5y
-5y=6x
so the answer is y=-6/5x
Answer:-55
Step-by-step explanation:-300 + 245 = -55