0.51
The hundredths place increases when it is higher than or equal to 5 in the thousandths place.
Let red marbles = X.
The probability is 1 out of 5, written as 1/5
1/5 in terms of red marbles is equal to the number of red marbles divided by 5x, where 5x is the total number of marbles.
1/5 = x/5x
Now you have 5x total marbles, x red and 4x blue.
Add 5 more red and the new probability is:
(x+5)/(5x+5) = 1/3
Simplify:
3x+15 = 5x+5
Now solve for x:
Subtract 3x from both sides:
15 = 2x +5
Subtract 5 from each side:
2x = 10
Divide both sides by 2:
x = 10/2
X = 5
There were originally 5 red marbles.
My answer-
Simplifying
5x + -14 = 8x + 4 Reorder the terms:
-14 + 5x = 8x + 4
Reorder the terms:
-14 + 5x = 4 + 8x Solving
-14 + 5x = 4 + 8x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8x' to each side of the equation.
-14 + 5x + -8x = 4 + 8x + -8x
Combine like terms: 5x + -8x = -3x
-14 + -3x = 4 + 8x + -8x
Combine like terms: 8x + -8x = 0
-14 + -3x = 4 + 0
-14 + -3x = 4
Add '14' to each side of the equation.
-14 + 14 + -3x = 4 + 14
Combine like terms: -14 + 14 = 0
0 + -3x = 4 + 14
-3x = 4 + 14 Combine like terms: 4 + 14 = 18
-3x = 18 <span>
Divide each side by '-3'.
x = -6
Simplifying
x = -6
If you need anything else on brainly let me know :)</span>
This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).