Question

In the diagram, AB is divided into equal parts. The coordinates of point A are _____, and the coordinates of point I are______ .

Answer 1

Answer:

The coordinates of point A are (-10,-4). The coordinates of I are (-3.875,-10.125).

Step-by-step explanation:

It is given that the the line AB is divided into equal parts. Therefor distance between two consecutive points are equal.

The point D is mid point of A and F.

$(x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

$(-8.25,-5.75)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})$

$-8.25=\frac{x-6.5}{2}$

$-16.50=x-6.5$

$-10=x$

$-5.75=\frac{y-7.5}{2}$

$-11.50=y-7.5$

$-4=y$

Therefore the coordinates of A are (-10,-4).

Similarly the pint H is midpoint of F and B.

$(-4.75,-9.25)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})$

The values of x and y are,

$x=-3$

$y=-11$

Therefore the coordinates of B are (-3,-11).

The point I is mid point of HB. H(-4.75,-9.25) and B(-3,-11).

$(x,y)=(\frac{-4.75-3}{2},\frac{-9.25-11}{2})$

$(x,y)=(-3.875,-10.125)$

Therefore the coordinates of I are (-3.875,-10.125).