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m_a_m_a [10]
3 years ago
6

Recipe ingredients remain jn a constant ratio no matter how many serving are prepared. Which table shows a possible ratio table

for ingredients C and Y for the given number of servings

Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

The last table (the bottom one)

Step-by-step explanation:

The ingredients having the same ratio means that, for every number of servings, we should have:

Y/X = constant.

So, for the first table when we have 1 serving, the quotient is:

Y/X = 2/1 = 2

when we have two servings:

Y/X = 3/2 = 1.5

The ratios are different.

Then this is not the correct option.

For the second table, when we have 1 serving the ratio is:

Y/X = 2/1 = 2

when we have two servings:

Y/X = 4/2 = 2

when we have 3 servings:

Y/X = 8/3 = 2.66

This is not the correct option.

For the third table:

1 serving:

Y/X = 2/1 = 2

2 sevings

Y/X = 3/2 = 1.5

This is not the correct option.

fourth table:

1 serving:

Y/X = 2/1 = 2

2 servings

Y/X = 4/2 = 2

3 servings

Y/X = 8/4 = 2

Here we can see that the ratio is always the same, then the ratio remains constant.

This is the table that shows a possible ratio for ingredients X and Y,

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3 1/8 x 3 3/5 in simplest form
iragen [17]
<span>3 1/8 x 3 3/5
= 25/8 x 18/5
= 5/4 x 9
= 45/4</span>
3 0
4 years ago
What equation results when you cross - multiply 17/d = 51/21
nekit [7.7K]

Answer:

 51d=357\\\\d=\frac{357}{51} \\\\d=7

Step-by-step explanation:

A proportion is an equation that defines that two ratios are equal.  When the terms of a proportion are cross multiplied, the cross products are equal.  Cross multiplication is the multiplication of the numerator of the first ratio by the denominator of the second ratio and the multiplication of the denominator of the first ratio by the numerator of the second ratio:

\frac{a}{b} =\frac{c}{d} \rightarrow ad=bc

Therefore:

\frac{17}{d} =\frac{51}{21} \\\\17*21=d*51\\\\357=51d\\\\Solving\hspace{3} for\hspace{3} d\\\\d=\frac{357}{51} \\\\d=7

6 0
3 years ago
I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x
joja [24]

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}

\mathbf{\rightarrow x = \dfrac{45}{20}}

\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}

\mathbf{\rightarrow x = \dfrac{9}{4}}

\mathbf{x \approx 2 \dfrac{1}{4}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
2 years ago
Read 2 more answers
PLZZZZ ANSWER ASAP TY
babymother [125]
So c is located at -50 from 0, and d is 50 from 0. we could just say that c+d=? 

0 is 50 away from c, so c=50, d is 50 away from 0 so d=50, now we just add 50+50=100, answer is 100

:) 
4 0
3 years ago
Let n be the middle number of three consecutive even integers. Write an expression for the sum of these integers.
Alisiya [41]
N - 1 = 1st number
n = middle number
n + 1 = 3rd number

(n - 1) + n + (n + 1) = 3n <== ur expression
6 0
3 years ago
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