2/5=6/15
1/3=5/15
11/15
yes. that would be the last one possible.
Answer:
do you have to show work?
Step-by-step explanation:
i will show work if its needed
<span>x-y=11 2x+y=19
x=11+y
2(11+y)+y=19
22+2y+y=19
3y=-3
y=-1
x=11-1=10</span>
"that were...."
-For my concern, please give more detail about this question and possibly explain.
There are 52 cards in a deck, half the cards aware red and half the cards are red.
First card being red is 26/52 = 1/2
After the first card is dealt there are 51 cards left and 26 are black so dealing a black card = 26/51
After 2 cards are dealt there are 50 cards left and 25 red ones left. The probability would be 25/50 = 1/2
The probability of all 3 happening = 1/2 x 26/51 x 1/2 = 13/102
Answer: 13/102