Six Subtract 2 Equals Four :)
The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Let the speed of one bicyclist=x mph
Let the speed of the other bicyclist=(x+3) mph
Hence:
Speed of one bicyclist:
3x+3(x+3)+2=98
3x+3x+9+2=98
6x=87
Divide both side by 6x
x=87/6
x=14.5 mph
Speed of the other bicyclist:
x+3 mph
14.5 mph+3 mph
=17.5 mph
Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
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brainly.com/question/18839894
Answer:
56.7
Step-by-step explanation:
2.7 x 21 = 56.7
Answer:
all real numbers
Step-by-step explanation:
simplify each side of the inequality
26 + 6b -- already fully simplified
2(3b + 4) → 6b + 8
26 + 6b ≥ 6b + 8
subtract 6b from both sides
26 ≥ 8
since this expression is true (26 is greater than 8), then the solution is all real numbers. any value could take the place of b because in the end, it will be canceled out by itself, resulting in 26 ≥ 8
F(x) + g(x)
3x-7+6x+4
=9x-3