<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D16%20-%206%20%5Csqrt%5B3%5D343%20%2B%2018%20%5Csqrt%5B5%5D243%20-%20%20%5Csqr

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3 years ago

t%7B196%7D%20" id="TexFormula1" title=" \sqrt[4]16 - 6 \sqrt[3]343 + 18 \sqrt[5]243 - \sqrt{196} " alt=" \sqrt[4]16 - 6 \sqrt[3]343 + 18 \sqrt[5]243 - \sqrt{196} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

VladimirAG [237]3 years ago

6 0

Answer:

Step-by-step explanation:

= 2- 6*7 + 18*3 - 14

=2-42+54-14

=2 + 12- 14

= 14-14

blagie [28]3 years ago

3 0

Answer:

the ans is 0

Step-by-step explanation:

=2- 6*7 + 18*3 - 14

=2-42+54-14

=2 + 12- 14

= 14-14

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Iced tea, x, costs $4 per gallon and lemonade, y, costs $6 per gallon. You need to purchase at least 9 gallons of drinks for a n

jekas [21]

The answer is (10,-5)

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3 years ago

1. What is the solution of the system?

andreyandreev [35.5K]

Answer:

The given system of equations has solutions below:

1) The solution is (2,3)

2) The solution is ( $\frac{-8}{7}, \frac{5}{7}$ )

3) The solution is infinitely many solutions

4) No solution

Step-by-step explanation:

Given system of equation are

$-x+2y=4\hfill (1)$

$-4x+y=-5\hfill (2)$

To solve equation by using elimination method

Multiply eqn (2) into 2

$-8x+2y=-10\hfill (3)$

Now subtracting (1) and (3)

$-x+2y=4$

$-8x+2y=-10$

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7x=14

x= $\frac{14}{7}$

$x=2$

Substitute x=2 in equation (1)

-2+2y=4

2y=4+2

$y=\frac{6}{2}$

y=3

Therefore the solution is (2,3)

2) Given equation is

$-2x+y=3\hfill (1)$

4y-4=x

Rewritting as below

$x-4y=-4\hfill (2)$

To solve equation by using elimination method

multiply (2) into 2

$2x-8y=-8\hfill (3)$

Adding (1) and (3)

-2x+y=3

2x-8y=-8

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-7y=-5

$y=\frac{5}{7}$

substitute $y=\frac{5}{7}$ in (1)

$-2x+\frac{5}{7}=3$

$-2x=3-\frac{5}{7}$

$-2x=\frac{21-5}{7}$

$x=-\frac{8}{7}$

Therefore the solution is ( $\frac{-8}{7},\frac{5}{7}$ )

3) Given equation is $6x+2y=10\hfill (1)$

$3x+y=5\hfill (2)$

equation (1) can be written as

2(3x+y)=10

$3x+y=\frac{10}{2}$

3x+y=5

Therefore equations (1) and (2) are same therefore it has infinitely many solutions

4) Given equation is $-x-2y=14\hfill (1)$

$-2x-4y=12\hfill (2)$

multiply equation (1) into 2

$-2x-4y=28\hfill (3)$

To solve equation by using elimination method

subtracting (2) and (3)

-2x-4y=28

-2x-4y=12

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$28\neq -12$

therefore it has no solution

4 0

3 years ago

Plz help its so confusing

aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = <u>3n/4</u>

Today after return of Jen 1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

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2 years ago

Mika wants to buy a condominium. He has the choice of buying it now or renting it with the option to buy at the end of 3 years.

mixer [17]

Answer:

Step-by-step explanation:

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3 years ago

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2 (5y-4)>32<br> Solve the inequality for y.

scoray [572]

Answer:

y > 4

Step-by-step explanation:

2 (5y-4)>32

Divide each side by 2

2/2 (5y-4)>32/2

5y-4 > 16

Add 4 to each side

5y-4+4 > 16+4

5y > 20

Divide each side by 5

5y/5 > 20/5

y > 4

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3 years ago

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