Answer:
test statistic = 12.115
Step-by-step explanation:
Given data :
std = 2.1 years
n = 10
( std )^2 = 4.41
<u>determine the test statistic</u>
apply a two-tailed test ( chi squared test for one population variance )
test statistic
λ^2 = 
( Referring to Exhibit 11-1 )
= ( 10 - 1 )*(2.1)^2 / 3.2761
= 12.115
Find the difference per row:
10 seats in the first row
30 seats in the sixth row:
30 -10 = 20 seats difference.
6-1 = 5 rows difference.
20 seats / 5 rows = 4 seats per row.
This means for every additional row, there are 4 more seats per row.
The equation would be:
Sn = S +(n-1)*d
Where d is the difference = 4
S = number of seats from starting row = 10
n = the number of rows wanted
S(11) = 10 + (11-1)*4
S(11) = 10 + 10*4
S(11) = 10 + 40
S(11) = 50
Check:
Row 6 = 30 seats
Row 7 = 30 + 4 = 34 seats
Row 8 = 34 + 4 = 38 seats
Row 9 = 38 + 4 = 42 seats
Row 10 = 42 + 4 = 46 seats
Row 11 = 46 + 4 = 50 seats.
<h2>
Therefore x=2 and y= 1</h2>
Step-by-step explanation:
Given equations are
and 
.........(2)
⇒
.......(1)
Equation (2)× 3 - Equation (1)
⇔
⇔-10y = -10
⇔y=1
Putting the value of y in equation (1) we get
⇔x =2
Therefore x=2 and y= 1
From my calculations, I have g = -10
