If a $24 dvd is marked down by 30% then the cost of the dvd would be 70% of the original cost. 100% - 30% = 70%
70% of 24 can be expressed as 0.7 x 24.
The answer is $16.80.
Hope this helps :)
Hello there.
<span>What is the measure of ∠GEH?
Answer: </span><span>141°</span>
Answer: 1. 7:10
2. 10 blue cans
15 yellow cans.
3. 4 cans of blue paint.
5 cans of yellow paint.
4. 2 blue cans and 3 yellow cans.
Step-by-step explanation:
1. 14 blue paint cans/20 yellow paint cans=
14/20=
7/10 ==> 7:10
2. 4+6 blue cans=10 blue cans
6+9 yellow cans=15 yellow cans.
3. 14-10=4 cans of blue paint.
20-15=5 cans of yellow paint.
4. 10 blue cans/15 yellow cans=
10/15=
2/3 ==> 2:3 ==> 2 blue cans and 3 yellow cans.
Answer:
p = -5
every element in the sequence is created by subtracting 3 from the pervious element.
Step-by-step explanation:
I am not sure you put every necessary information here.
but I'd the visible information is truly everything, then it's is trivial.
the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.
we suspect this is the rule and keep trying.
1 -3 = -2
hey it works.
and -8 -3 = -11
hey, also correct.
and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.
therefore,
p = -2 -3 = -5
the rule is
an = an-1 - 3
<h3>
Answer: (4,2)</h3>
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Explanation:
C is at (0,0). Ignore the other points.
Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.
Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"
So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.
All of this is shown in the diagram below.