All categories

3 years ago

What is the slope-intercept form of the function described by this table

1 answer:

swat323 years ago

3 0

$x_1=1 \\ y_1=-2 \\ \\ x_2=2 \\ y_2=-6 \\ \\
m=\frac{y_2-y_1}{x_2-x_1}=\frac{-6-(-2)}{2-1}=\frac{-6+2}{1}=\frac{-4}{1}=-4 \\ \\
y=-4x+b \\
x=1, y=-2 \\
-2=-4 \times 1+b \\
-2=-4+b \\
-2+4=b \\
b=2 \\ \\
\boxed{y=-4x+2}$

You might be interested in

-8 is a term true or false

kupik [55]

True, -8 is a term. Have a great day.

8 0

3 years ago

I don’t understand the question

kipiarov [429]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

$- 13 {x}^{2} \: has \: only \: one \: term \: and \: highest \: degree \: is \: 2 \\$

1) Option d) Monomial degree 2

$- 8 {y}^{7} - 3 \: has \: two \: terms \: and \: highest degree \: is \: 7$

2) Option c) Binomial degree 7

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

6 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

Solve the system of equations

Nadya [2.5K]

So we have the equations:

y - 4x = 2 --- equation 1

5y - 2x = 1 --- equation 2

(equation 2) * 2

10y - 4x = 2 --- equation 3

(equation 2) - (equation 3)

-9y = 0 so y= 0 and thus x = -1/2

Hope that helps!

4 0

2 years ago

What is the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15

Elden [556K]

9514 1404 393

Answer:

x + 3y = 9

Step-by-step explanation:

The parallel line will have the same x- and y-coefficients. The new constant can be found by using the (x, y) values of the given point.

x + 3y = (6 +3(1)) = 9

The equation of the parallel line is ...

x + 3y = 9

8 0

2 years ago