Question

What is the slope-intercept form of the function described by this table

Answer 1

$x_1=1 \\ y_1=-2 \\ \\ x_2=2 \\ y_2=-6 \\ \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{-6-(-2)}{2-1}=\frac{-6+2}{1}=\frac{-4}{1}=-4 \\ \\ y=-4x+b \\ x=1, y=-2 \\ -2=-4 \times 1+b \\ -2=-4+b \\ -2+4=b \\ b=2 \\ \\ \boxed{y=-4x+2}$