<span>Let the original number of seats in a row be x;
</span>Let the number rows be y;
( x + 3) * (y - 2 )= 72 and x * y = 72 => 72 + 3 * y - 2 * x = 72 => 3 * y = 2 * x;
=> x is divisible by 3;
1. x = 3 => y = 72 / 3 => y = 24;
2. x = 6 => y = 72 / 6 => y = 12;
3. x = 9 => y = 72 / 9 => y = 8;
4. x = 12 => y = 72 / 12 =. y = 6;
5. x = 24 =. y = 72 / 24 => y = 3;
6. x = 36 => y = 72 / 36 => y = 2;
7. x = 72 => y = 72 / 72 => y = 1;
My analysis tell me that the right answer is 9 seats in a row and 8 rows;
The original number in each row is 9.
Answer:
1/6 qt. of milk.
Step-by-step explanation:
1/3 /2= 1/6
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:
Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:
By substitution:
Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:
Zero Product Property:
Now, by testing values for t<1, 1<t<4, and t>4, we see that:
So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
Answer:
q= -3
Step-by-step explanation:
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
