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3 years ago

Which is one way to check 102 ÷ 6 = 17?

Mathematics

2 answers:

zmey [24]3 years ago

5 0

Your answer is c 100 ÷ 5 = 20

Bond [772]3 years ago

3 0

Solution:

102 ÷ 6 = 17

As you can see , 102 has unit digit of 2 ,it means it is divisible by 2

Sum of digits of (102) = 1 + 2 =3, it means it is divisible by 3 also.

So , if a number is divisible by 2 and 3 it means it is divisible by 6 also.

Option (A) and Option (C) are true options which are

105 ÷ 5 = 21, and 100÷5 =20

The reason being if you will look at the unit digit of 105 and 100 , it is 5 and 0. So if a number have unit digit either 5 or 0 it is divisible by 5.

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Mia and Carlos are hiking on a trail where they start 16 miles apart. If Mia can average 2.3 miles per hour while hiking and Car

kherson [118]

Answer:

I'm not sure but if this is on a calculus paper, this may put you on the right track?

Step-by-step explanation:

definate integral from 2.3 to 2.5 would equal 3.2, i don't know what to do with that information but i hope that helps you.

4 0

2 years ago

Ashton needs $120 but has only saved 60% so far. How much more money does he need

Kamila [148]

Hello there! Ashton needs 48 more dollars.

Well, to start, you want to find 60% of 120. To do this, you first have to convert 60% into a decimal by dividing it by 100.

60/100 = 0.6

Next, multiply 0.6 by your total needed, 120, to finish finding 60% of 120.

120 x 0.6 = 72.

So he already has 72 dollars, but how many more does he need? You can find this by subtracting 72 from 120.

120 - 72 = 48.

So, this means he needs 48 more dollars. I hope this helps and have a great rest of your day! Please let me know if you need further help with this question. :)

3 0

3 years ago

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0