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2 years ago

True or False: The more confident you want to be, the smaller your confidence interval will be

Mathematics

1 answer:

Katen [24]2 years ago

5 0

Answer:

False

Step-by-step explanation:

it depends on the person, if you try to boast your confidence it you may either be more confident or you will lose all of your current confidenc.

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What is the cost of each chicken and what is the cost of each duck

zimovet [89]

Answer: $8 chicken $5 duck

Step-by-step explanation:

50x+30y=550

x=8

y=5

400+150=550

7 0

3 years ago

Read 2 more answers

The answer is not A or B

Nat2105 [25]

Answer:

C) 4

Step-by-step explanation:

Arcs on one side of the diameter adds upto 180°.

Therefore,

$(2 + 17x) \degree + 54 \degree + 56 \degree = 180 \degree \\ \\ (2 + 17x) \degree + 110 \degree = 180 \degree \\ \\ (2+ 17x) \degree = 180 \degree - 110 \degree\\ \\ (2 + 17x) \degree = 70 \degree \\ \\ 2 + 17x = 70 \\ 17x = 70 - 2 \\ \\ x = \frac{68}{17} \\ \\ x = 4$

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2 years ago

Read 2 more answers

When a number is divided by 5 the answer is 3 remainder 4, what is that number?

skelet666 [1.2K]

We know that 5 fits entirely into our number three times, and then there's a remainder of 4.

If 5 fits three times exactly, it means that our number is at least 15 (5x3).

From here, we have a remainder of 4, which leads to 15+4=19

5 0

2 years ago

Help plssssssssssssss

Svet_ta [14]

I believe it is option 2, sorry if incorrect

4 0

2 years ago

Help with Pre Calculus

marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. $x(2x^2-x-15)$ . So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\$ . So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}$

4 0

1 year ago