Answer:
x=1
Step-by-step explanation:
We have,
h(x) = 5-2x
h(x)=3
Now,
h(x)=5-2x=3
or,5-2x=3
or,5-3=2x
or,2/2=x
Therefore, x=1 when h(x)=3
This question is unsolvable this might be a trick question but it is not solvable. Hope this helps! ;D
<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>
Answer:
![i^{97}-i=0](https://tex.z-dn.net/?f=i%5E%7B97%7D-i%3D0)
Step-by-step explanation:
<u>Powers of The Imaginary Unit</u>
The imaginary unit i is defined as
The first powers of i are
![i^0=1](https://tex.z-dn.net/?f=i%5E0%3D1)
![i^1=i](https://tex.z-dn.net/?f=i%5E1%3Di)
![i^2=(\sqrt{-1})^2=-1](https://tex.z-dn.net/?f=i%5E2%3D%28%5Csqrt%7B-1%7D%29%5E2%3D-1)
![i^3=i.i^2=-i](https://tex.z-dn.net/?f=i%5E3%3Di.i%5E2%3D-i)
![i^4=i^2.i^2=1](https://tex.z-dn.net/?f=i%5E4%3Di%5E2.i%5E2%3D1)
And so on the cycle repeats every four numbers. To find the value of
we can find the remainder of 96/4=0. So ![i^{96}=i^0=1](https://tex.z-dn.net/?f=i%5E%7B96%7D%3Di%5E0%3D1)
The given expression is
![i^{97}-i](https://tex.z-dn.net/?f=i%5E%7B97%7D-i)
Factoring
![i(i^{96}-1)](https://tex.z-dn.net/?f=i%28i%5E%7B96%7D-1%29)
Since ![i^{96}=1](https://tex.z-dn.net/?f=i%5E%7B96%7D%3D1)
![=i(1-1)=0](https://tex.z-dn.net/?f=%3Di%281-1%29%3D0)
The required value is 0
Answer:
The ships are 66 meters apart.
Step-by-step explanation:
For the sake of convenience, let us label ships A and B
As shown in the figure, the distances to the ships from right triangles.
The distance to the ship A is
and it is given by
![tan (61^o)= \dfrac{50}{d_1}](https://tex.z-dn.net/?f=tan%20%2861%5Eo%29%3D%20%5Cdfrac%7B50%7D%7Bd_1%7D)
![d_1=\dfrac{50}{tan (61^o)}](https://tex.z-dn.net/?f=d_1%3D%5Cdfrac%7B50%7D%7Btan%20%2861%5Eo%29%7D)
![\boxed{d_1= 27.71m}](https://tex.z-dn.net/?f=%5Cboxed%7Bd_1%3D%2027.71m%7D)
And the distance to the ship B is
and is given by
![tan (28^o)= \dfrac{50}{d_2}](https://tex.z-dn.net/?f=tan%20%2828%5Eo%29%3D%20%5Cdfrac%7B50%7D%7Bd_2%7D)
![d_2=\dfrac{50}{tan (28^o)}](https://tex.z-dn.net/?f=d_2%3D%5Cdfrac%7B50%7D%7Btan%20%2828%5Eo%29%7D)
![\boxed{ d_2=94.04m}](https://tex.z-dn.net/?f=%5Cboxed%7B%20d_2%3D94.04m%7D)
Therefore, the distance
between the ships A and B is
![d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}](https://tex.z-dn.net/?f=d%3D%20d_2-d_1%3D94.04-27.7%5C%5C%5C%5C%5Cboxed%7Bd%3D66m%7D)
In other words, the ships are 66 meters apart.
Answer:
2
Step-by-step explanation:
rise over run = y/x
3/1.5= 2