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Aleksandr [31]
3 years ago
12

If a 12-foot flag pole casts a 4.8-foot shadow, how tall is a flag pole that casts an 8-foot shadow?

Mathematics
1 answer:
andre [41]3 years ago
5 0

Answer:

20-foot flag

Step-by-step explanation:

12-foot flag casts 4.8-foot shadow,

which also means that:

4.8-foot shadow is casted by a 12-foot flag

Lets start by find the length of the flag that will cast a 1-foot shadow.

4.8-foot shadow -----> 12-foot flag

1-foot shadow ----->  12 ÷ 4.8 = 2.5-foot flag

Now we can find the flag that will cast a 8-foot shadow.

1-foot shadow ----->  2.5-foot flag

8-foot shadow  ----->  8 x 2.5-foot  = 20-foot flag

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A football team has a net yardage of −28 1/3
Pavlova-9 [17]

Answer: 58 1/3 yards

Step-by-step explanation:

From the question, we are informed that a football team has a net yardage of −28 1/3 yards on a series of plays and that the team needs a net yardage of 30 yards to get a first down.

The number of yards that they have to get on their next play to get a first down would be calculated as:

= 30 - -28 1/3

Note that minus × minus = plus

= 30 + 28 1/3

= 58 1/3 yards

7 0
3 years ago
I'm stuck on this one! Help please?
zepelin [54]
Expand 

(4a + 12 = 12 + 4a)

Cancel 4a on both sides

12 = 12

Since both sides are equal there are infinitely many solutions

Process of elimination, cross out d) no solution. But I would best go with C)
7 0
4 years ago
6. What is the slope of the line given by the equation y = 4x +12?
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Answer:

4

Step-by-step explanation:

y = 4x + 12

In y = mx+b

The coefficient of x (m) is the slope.

So the slope is 4

8 0
3 years ago
Read 2 more answers
How can she find the coordinates of the new point without graphing the point?
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3 0
3 years ago
Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t
SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be h meters and h= h_1+h_s.

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ.                                        In ΔSPR.

⇒ tan(60) = \frac{h_1}{x} ...equation (i)        ⇒ tan (30)=\frac{h_1}{x+50}  ...equation (ii)

Dividing equation (i) and (ii)

⇒ \frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}

⇒ 3 = \frac{x+50}{x}

⇒ 3x=x+50

⇒ 3x-x=50

⇒ 2x=50

⇒ x=\frac{50}{2}

⇒ x=25 meters

To find h_1 plugging x=25 in equation (i)

⇒ h_1=x\times tan(60)

⇒ h_1=25\times 1.73

⇒ h_1=43.25 meters

The height of the cliff from ground :

⇒ h= h_1+h_s

⇒ h= 43.25+1.8

⇒ h=45.05 meters

The cliff is 45 m tall to the nearest meter.

8 0
4 years ago
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