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abruzzese [7]
3 years ago
10

If the radius of a circle is 14 ft, then the diameter of the circle is _____.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0
Radius to Diameter = 14*2= 28 feet
Diameter to radius= 28÷2= 14 radius

When given the radius, multiply it by 2 to get the diameter.

ANSWER: B) 28 feet

Hope this helps! :)
miv72 [106K]3 years ago
6 0

14 \times 2 = 28
its B.) 28ft
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2. A rectangular plot of land is 0.4 kilometer long and 0.07 kilometer wide. What is its
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3 years ago
Based on a sample of 100 employees a 95% confidence interval is calculated for the mean age of all employees at a large firm. Th
babymother [125]

Answer:

a

\= x  =  40.85

b

E = 5.85

Ca  

   t_c =  2.08

Cb

   t_c  =   1.282

Explanation:

From the question we are told that

     The sample size is n  =  100

     The upper limit of the 95% confidence interval is  b =  47.2 years

     The lower limit of the 95% confidence interval is   a =  34.5 years

Generally the sample mean is mathematically represented as

         \= x  =  \frac{a + b }{2}

=>    \= x = \frac{47.2 + 34.5 }{2}

=>    \= x  =  40.85

Generally the margin of error is mathematically represented as

         E =  \frac{b- a }{ 2}

=>      E =  \frac{47.2- 34.5 }{ 2}

=>      E = 5.85

Considering question C a  

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

The  sample size is  n =  22

Given that the sample size is not sufficient enough i.e n < 30 we will make use of the student t distribution table  

Generally the degree of freedom is mathematically represented as

           df =  n- 1

=>        df =  22 - 1

=>        df =  21

Generally from the student  t  distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom  of  21 is  

   t_c =t_{\frac{\alpha }{2} ,  21  } =  2.08

Considering question C b

From the question we are told the confidence level is  80% , hence the level of significance is    

      \alpha = (100 - 80 ) \%

=>   \alpha = 0.20

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   t_c  =Z_{\frac{\alpha }{2} } =  1.282

4 0
3 years ago
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