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EleoNora [17]
4 years ago
9

Y = kx The constant of variation in this equation is???? y = 4x

Mathematics
2 answers:
Katena32 [7]4 years ago
6 0
Y = kx

Where 'k' is the constant of variation. 

y = 4x means that 4 is the constant of variation. 

Answer: 4
Mekhanik [1.2K]4 years ago
4 0
Y = 4x shows that 4 is the constant of variation. 
<span>Answer: 4, the number next to x.</span>
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6p ≥ −24 plz help me
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Divide both sides by the coefficient 6 to get p <span>≥ −24/6 = -4

p </span><span>≥ −4</span>
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3 years ago
I dont know plz help
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3 years ago
What is the length of PQ¯¯¯¯¯?
timofeeve [1]
Since you don't have any angle and its opposite side, you cannot establish the ratio for the law of sines, so you must use the law of cosines.

c^2 = a^2 + b^2 - 2ac \cos C

Let's change it for this problem.

r^2 = p^2 + q^2 - 2pq \cos R

r^2 = 9^2 + 6^2 - 2(9)(6) \cos 34^\circ

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5 0
4 years ago
Read 2 more answers
Phyllis invested $11,500, a portion earning a simple interest rate of
Cerrena [4.2K]

Answer:

He invested $8500 with rate 3 1/5%

He invested $3000 with rate 3%

Step-by-step explanation:

* <em>Lets revise the rule of the simple interest</em>

- Simple interest I = PRT, where P in the money invested, R is the

 interest rate and T is the time of investment

- Phyllis invested $11,500

- A portion earning a simple interest rate of 3 1/5% (3.2%) per year

- The rest earning a rate of 3% per year

- After one year the total interest earned on these investments

 was $362.00

- We need to find the amount of money invested in each rate

* Assume that he invested $x with rate 3 1/5% and $y with rate 3%

∵ He invested $11,500 in both rates

∴ x + y = 11,500 ⇒ (1)

∵ He invested $x with 3 1/5%

∵ P = $x

∵ R = 3.2/100 = 0.032

∵ T = 1

∴ I_{1}=x(0.032)(1)

∴ I_{1}=0.032x

∵ He invested $y with 3%

∵ P = $y

∵ R = 3/100 = 0.03

∵ T = 1

∴ I_{2}=y(0.03)(1)

∴ I_{2}=0.03y

∵ The total interest was $362.00

- The total interest = I_{1} + I_{2}

∴ 0.032x + 0.03y = 362.00 ⇒ (2)

<em>We have system of equations</em>

x + y = 11,500 ⇒ (1)

0.032x + 0.03y = 362.00 ⇒ (2)

Multiply equation (1) by -0.03 to eliminate y

-0.03x - 0.03y = 345 ⇒ (3)

Add equations (2) and (3)

0.002x = 17

Divide both sides by 0.002

x = 8500

Substitute the value of x in equation (1)

8500 + y = 11,500

Subtract 8500 from both sides

y = 3000

* He invested $8500 with rate 3 1/5%

* He invested $3000 with rate 3%

7 0
3 years ago
9) If x=-4 is a zero of a polynomial p(x), then the zero of p(x² - 6x + 5) is​
spin [16.1K]

If x=-4 is a zero of p(x), then we can write

p(x) = (x + 4) q(x)

for another polynomial q(x).

Note that x^2 - 6x + 5 = (x - 5)(x - 1). Then

p(x^2 - 6x + 5) = p\bigg((x-5)(x-1)\bigg) \\\\ ~~~~~~~~~~~~ = ((x - 5)(x-1) + 4) q\bigg((x-5)(x-1)\bigg) \\\\ ~~~~~~~~~~~~ = (x^2 - 6x + 9) q(x^2 - 6x + 5) \\\\ ~~~~~~~~~~~~ = (x - 3)^2 q(x^2 - 6x + 5)

so that \boxed{x = 3} is a root of p(x^2 - 6x + 5).

5 0
2 years ago
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