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WARRIOR [948]
2 years ago
10

Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3? Assume x is not equal to 0,y is not equal to 0

Mathematics
2 answers:
VladimirAG [237]2 years ago
7 0
I am going to assume that "v" is meant to be a "y"
the answer is b. (3)/(5x^6 y^6)
Alex777 [14]2 years ago
6 0

Answer:

The correct option is b.

Step-by-step explanation:

The given expression is

\frac{-9x^{-1}y^{-9}}{-15x^5y^{-3}}

It can be written as

\frac{-9}{-15}\times \frac{x^{-1}}{x^5}\times \frac{y^{-9}}{y^{-3}}

Using the property of exponent we get

\frac{3}{5}\times x^{-1-5}\times y^{-9+3}       [\because \frac{x^m}{x^n}=x^{m-n}]

\frac{3}{5}\times x^{-6}\times y^{-6}

\frac{3}{5}\times \frac{1}{x^{6}}\times \frac{1}{y^{6}}       [\because \frac{1}{x^n}=x^{-n}]

\frac{3}{5x^{6}y^{6}}

Therefore the correct option is b.

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Answer:

Step-by-step explanation:

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-2x+6=6  and  -2x+6=-6

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Answer:

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Step-by-step explanation:

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3 years ago
n a survey of 331 customers, 66 say that service is poor. You select two customers without replacement to get more information o
yaroslaw [1]

Answer:

3.93% probability that both say service is poor

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The customers are chosen without replacement, and the order in which they are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

What is the probability that both say service is poor?

Desired outcomes:

Two saying it is poor, from a set of 66. So

D = C_{66,2} = \frac{66!}{2!(66-2)!} = 2145

Total outcomes:

Two customers from a set of 331. So

T = C_{331,2} = \frac{331!}{2!(331-2)!} = 54615

Probability:

p = \frac{D}{T} = \frac{2145}{54615} = 0.0393

3.93% probability that both say service is poor

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2 years ago
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75/4=3/100

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