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Svetlanka [38]
3 years ago
13

HOW can you find the number of permutations of a set of objects?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0
Hope this handy formula helps!
P(n,r)=\frac{n!}{n-r!}
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What’s the slope of this equation
Vinvika [58]

Answer:

<em>m</em> = -2

General Formulas and Concepts:

<u>Algebra</u><em><u> </u></em><u>I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Function y = -2x + 5

<u>Step 2: Break Function</u>

Slope <em>m</em> = -2

y-intercept <em>b</em> = 5

5 0
3 years ago
How do you do this?Can you help me with the steps? I don't really get this a lot
polet [3.4K]
Before you do the steps, change the fractions given to improper fractions:
2 2/3 = 8/3
3 1/6 = 19/6

Now, I think the first step they want you to write is:
8/3 (divided by) 19/6

When you divide two fractions, it's the same as multiplying the first fraction by the reciprocal of the second fraction. (A reciprocal is a fancy way of saying you flip the fraction)
So the next step will look like this:
8/3 x 6/19

With this setup, you can cross simplify the fractions so that they look like this:
8/1 x 2/19
When you multiply this, you get 16/19
Let me know if you have any questions!
4 0
3 years ago
Read 2 more answers
Make x the subject of the formula: <br> Y=3x^2+4
Rzqust [24]

Answer:

see explanation

Step-by-step explanation:

given

y = 3x² + 4 ( isolate the term in x by subtracting 4 from both sides )

y - 4 = 3x² ( divide both sides by 3 )

\frac{y-4}{3} = x² ( take the square root of both sides )

\sqrt{\frac{y-4}{3} } = x, or

x = \sqrt{\frac{y-4}{3} }

6 0
4 years ago
PLEASE ANSWER THESE 4 QUESTIONS WILL MARK BRANLIEST I AM TIMED :)
Veronika [31]

Answer:

its 3.

Step-by-step explanation:

HOpe that helped

4 0
3 years ago
Solve using the quadratic formula<br> 2x^2+x+67=0
telo118 [61]

Answer:

\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Multiple Roots
  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: \displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

<u>Algebra II</u>

  • Imaginary Root <em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + x + 67 = 0

<em>a</em> = 2

<em>b</em> = 1

<em>c</em> = 67

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [Quadratic Formula]:                                                  \displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}
  2. Multiply:                                                                                                             \displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}
  4. [√Radical] Multiply:                                                                                           \displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}
  5. [√Radical] Subtract:                                                                                          \displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}
  6. [√Radical] Simplify:                                                                                           \displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}
3 0
3 years ago
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