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SVETLANKA909090 [29]
4 years ago
15

Find the average rate of change for f(x)=x+6 over the interval [4,8]

Mathematics
2 answers:
svlad2 [7]4 years ago
6 0

<u>Answer:  </u>

The Average rate of change for f(x) = x+6 over the interval (4,8) is 1

<u>Solution:  </u>

We define the Average rate of function f(x) over the interval (a, b) as

\frac{f(b)-f(a)}{b-a}   --- eqn 1

From question, given that

f(x) =x+6 --- eqn 2

The interval is (4,8) .hence we say a = 4 and b = 8

The average rate of change for f(x) = x + 6 is given by using eqn 1

\frac{f(8)-f(4)}{8-4} --- eqn 3

Where, by using eqn 2 , we get f(8) = 8+6 =14 and f(4) = 4+6 =10

Such that the required value would be f(8)-f(4) = 14-10 = 4

By substituting the values of f(8) and f(4) in eqn 3 ,the average rate of change for the given expression is  

=\frac{14-10}{8-4}=\frac{4}{4}=1

Hence the Average rate of change for f(x) = x+6 over the interval (4,8) is 1

beks73 [17]4 years ago
3 0

Solve for f(x) using both 4 and 8:

f(x) = 4+6 = 10

f(x) = 8+6 = 14

Find the difference between the answers:

The difference between the two answers is 14-10 = 4

Find the difference between the interval:

The difference between 4 and 8 is: 8-4 = 4

The rate of change is the change in the answers over the difference in the interval:

The rate of change is 4/4 = 1

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A group conducted a poll of 2083 likely voters just prior to an election. The results of the survey indicated that candidate A w
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Step-by-step explanation:

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\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

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\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }

Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

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