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MrRissso [65]
4 years ago
13

Which is the simplified form of the expression 3(7/5x + 4) - 2(3/2 - 5/4x)

Mathematics
1 answer:
faltersainse [42]4 years ago
6 0

Answer:

Step-by-step explanation:

I think you meant 3([7/5]x + 4) - 2(3/2 - [5/4]x).  If that's the case, then identify the LCD:  It is 20.  Multiply both [7/5]x + 4 and 3/2 - [5/4]x by 20 and then divide the resulting expression by 20:

3(28x + 80) - 2(30 - 25x)

------------------------------------

               20

Next, perform the indicated multiplication:

 84x + 240 - 60 + 50x

----------------------------------

                 20

This simplifies to:

 34x + 180        17x + 9

---------------- = ----------------

       20                 10

Next time, please share the answer choices.

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The complement of an angle is 25 less than 3 times the angles itself. Find the measure of each
Semenov [28]

Answer: 28.75° and 61.25°

Step-by-step explanation:

A complementary angle equals 90°.

Let the measure of the angle be a

Therefore, its complement will be:

= 90-a.

The complement of an angle is 25 less than 3 times the angles itself can be written as:

90-a = 3a - 25

90 + 25 = 3a + a

115 = 4a

a = 115/4

a= 28.75

Since the angle is 28.75°, the complement will be:

= 90° - 28.75°

= 61.25°

The angles are 28.75° and 61.25°

6 0
4 years ago
The red blood cell counts​ (in millions of cells per​ microliter) for a population of adult males can be approximated by a norma
skad [1K]

Answer:

(a) Minimum red blood cells 5.744 million cells per micro liter

(b) Maximum red blood cells 5.068 million cells per micro liter.

Step-by-step explanation:

Z-score formula is = \frac{x-u}{Standard deviation}

Z-score = \frac{x-5.5}{0.4}

The value of z-score is 0.61 so then x will be;

x = 5.744

The minimum red blood cells count that can in top is 27% of count which is 5.744 million cells per micro liter.

Z-score = \frac{x-5.5}{0.4}

The value of z-score is 0.14 so then x will be;

x = 5.068

The maximum red blood cells count that can be in top is 14% of count which is 5.068 million cells per micro liter.

6 0
3 years ago
I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

7 0
3 years ago
Please help with this one question that I've been stuck on!!! In a random sample of 74 homeowners in a city, 22 homeowners said
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6 0
3 years ago
Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
4 years ago
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