Answer:
9
Step-by-step explanation:
→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:
\begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}
a
2
+b
2
=c
2
x
2
+(x−3)
2
=(x+3)
2
x^2+x^2-6x+9=x^2+6x+9x
2
+x
2
−6x+9=x
2
+6x+9
→Subtract x^2-6x+9x
2
−6x+9 from both sides:
x^2 = 12xx
2
=12x
→Subtract 12x from both sides:
x^2 -12x=0x
2
−12x=0
→Factor out x:
x(x-12)=0x(x−12)=0
→Separate, set = to 0, and solve:
\begin{gathered}x = 0\\x -12=0\end{gathered}
x=0
x−12=0
→ Add 12 to both sides: x = 12x=12
→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.
→All we need to do is take 12, and plug it into the equation for the shortest leg.
\begin{gathered}x - 3=?\\12-3=9\end{gathered}
x−3=?
12−3=9
500 divided by 60 = 8.33... (but you round it to 8)
it would take her about 8 minutes.
Answer: (-2, 5) and (2, -3)
<u>Step-by-step explanation:</u>
Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:
y - intercept = (0, 1) 2nd point = ( -1, 1).
Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):
vertex = (1, -4) 2nd point (y-intercept) = (0, -3)
<em>see attached</em> - the graphs intersect at two points: (-2, 5) and (2, -3)
Answer:
D) y=-4x+2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-2-6)/(1-(-1))
m=-8/(1+1)
m=-8/2
m=-4
y-y1=m(x-x1)
y-6=-4(x-(-1))
y-6=-4(x+1)
y=-4x-4+6
y=-4x+2
If it were a complete circle, its circumference would be
(π) x (diameter) = (π) x (2R) = 70 π inches .
Since it's only half of the circle, the length of the curved part is
70 π / 2 = 35 π = <em>109.9 inches</em> .
