4y=-5x+15
y=-5/4x+15/4
y-1/2=4/5(x-1/2)
y-1/2=4/5x-2/5
y-5/10=4/5x-4/10
y=4/5x+1/10
Answer:
It'll take 3 h before Lenore catch up to Sheila.
Step-by-step explanation:
To solve this problem we first need to calculate the relative speed between the two. Since they're going at the same direction we need to subtract their individual speeds if their directions were oposite we would have to sum their speeds. In this case we have:
relative speed = Lenore speed - Sheila speed
relative speed = 60 - 45 = 15 mph
Since Sheila left 1 h before Lenore and she drove at a rate of 45 mph, then she had covered a distance of:
distance = time*speed = 1*45 = 45 miles
Before Lenore left, so in order for Lenore to catch up to Sheila she needs to cover that distance at a relative speed of 15 mph.
time = distance/(relative speed) = 45/15 = 3 h
It'll take 3 h before Lenore catch up to Sheila.
Answer:
hope this helps
Step-by-step explanation:
The correct answer to this question will be the yellow box which is <5 less than five
