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Zepler [3.9K]
3 years ago
13

Find the Y intercept of a line that passes through 3, -5 and has a slope of -1

Mathematics
1 answer:
RSB [31]3 years ago
6 0

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-5})~\hspace{10em} slope = m\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-1(x-3)\implies y+5=-x+3


\bf y=-x\underset{\uparrow }{-2}\leftarrow \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hfill \stackrel{y-intercept}{(0,-2)}

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2x + y = 12<br> 4x - 3y = 2
7nadin3 [17]

Answer:

The value of x for equation is 3.4

The value of y for equation is 5.2  

Step-by-step explanation:

Given as :

The two linear equation are

2 x + y = 12           ........A

4 x - 3 y = 2              .........B

Now, Solving both equations , we get

3 × ( 2 x + y ) + (4 x - 3 y) = 3 × 12 - 2

Or, 6 x + 3 y + 4 x - 3 y = 36 - 2

Or, (6 x + 4 x) + (3 y - 3 y) = 34

Or, 10 x + 0 = 34

∴  x = \dfrac{34}{10}

i.e x = 3.4

So, The value of x for equation , x = 3.4

Put the value of x into eq A

∵ 2 x + y = 12

Or, y = 12 - 2 x

Or, y = 12 - 2 × 3.4

Or, y = 12 - 6.8

∴ y = 5.2

So, The value of y for equation , y = 5.2

Hence, The value of x for equation is 3.4  and The value of y for equation is  5.2   Answer

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The local park has 4 bike racks. Each bike rack can hold 15 bikes. There are 16 bikes in the bike racks. What expression shows t
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What is the value of the expression below when y=2 6y^2 +8y-9
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Answer:

6y^2+7

Step-by-step explanation:

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Read 2 more answers
HELP!!!!!!!!!!!!!!!!!!!!!!!!
Olegator [25]

Answer:

Part) A. Part B and Part C see the explanation

Step-by-step explanation:

Part A) Translate Triangle ABC 6 units horizontally How are the values in the ordered pairs affected by the translation?

If the translation is 6 units horizontally, that means that each vertex of the ABC pre-image is going to move 6 units to the right, i.e. each x-coordinate of the ABC pre-image is going to increase by 6 units and each y-coordinate of the ABC pre-image is going to remain the same.

Part B) Translate Triangle ABC -3 units vertically How are the values in the ordered pairs affected by the translation?

If the translation is -3 units vertically, that means that each vertex of the ABC pre-image is going to move 3 units down, i.e. each x-coordinate of the ABC pre-image is going to remain the same and each y-coordinate of the ABC pre-image is going to decrease by 6 units.

Part C) How could you determine the coordinates of the vertices of a translated image without using a graph?

we know that

The coordinates of the image vertices can be determined through the rule of the translation

so

In the part A) the translation is +6 units horizontally (6 units at right)

therefore

The rule of the translation of the pre-image to the image is equal to

(x,y) ------> (x+6,y)

<u><em>Example</em></u>

The coordinates of the pre-image A(-4,1)

To obtain the coordinates of the image A' apply the rule of the translation

A(-4,1)--------> A'(-4+6,1)

A(-4,1)--------> A'(2,1)

In the part B) the translation is -3 units vertically (3 units down)

therefore

The rule of the translation of the pre-image to the image is equal to

(x,y) ------> (x,y-3)

<u><em>Example</em></u>

The coordinates of the pre-image A(-4,1)

To obtain the coordinates of the image A' apply the rule of the translation

A(-4,1)--------> A'(-4,1-3)

A(-4,1)--------> A'(-4,-2)

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3 years ago
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