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3 years ago

15

I need the answer please

1 answer:

lutik1710 [3]3 years ago

4 0

5 inches : 2 feet

÷2.5

120 inches : 48 feet

÷2.5

answer: 48 feet

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The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh

expeople1 [14]

Answer:

The correct answer is:

The volume of the triangular prism is equal to the volume of the cylinder

Step-by-step explanation:

Given that there are two figures

1. A right triangular prism and

2. Right cylinder

Area of cross section of prism is equal to Area of cross section of cylinder.

Let this value be <em>A</em>.

Also given that Height of prism = Height of cylinder = <em>6</em>

Volume of a prism is given as:

$V_{Prism} = \text{Area of cross section} \times Height$

$V_{Prism} = A \times 6 ........ (1)$

Cross section of cylinder is a circle.

<em>Area of circle</em> is given as: $\pi r^{2}$

Area of cross section, A = $\pi r^{2}$

Volume of cylinder is given as:

$V_{Cylinder} = \pi r^{2} h\\\Rightarrow V_{Cylinder} = A \times h\\\Rightarrow V_{Cylinder} = A \times 6 ...... (2)$

From equations (1) and (2) we can see that

$V_{Prism}=V_{Cylinder}$

Hence, the correct answer is:

Volume of prism is equal to the volume of cylinder.

3 0

2 years ago

In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalizat

Viktor [21]

Answer:

Sample mean for solution 1: 19.27; sample mean for solution 2: 10.32

Step-by-step explanation:

To find the sample mean, find the sum of the data values and divide by the sample size.

For solution 1, the sum is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10; this gives us

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

6 0

3 years ago

Find the area of this circle. Use 3 for T.<br> A = 7r2<br> 4 in<br> [?] in2<br> Enter<br> Help!!!!!

Allushta [10]

Sorry I don’t know the answer I’ve been looking for the similar one wish I could help

6 0

3 years ago

Help please! anything will help thanks ya'll.!

zzz [600]

The cosine of A is (adjacent side)/(hypotenuse) = 55/73. Do the division, then find the angle whose cosine is that number. The whole thing takes maybe 6 or 7 seconds with your calculator. It's choice-B.

6 0

3 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago