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Lera25 [3.4K]
3 years ago
15

I need the answer please

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

5 inches : 2 feet

          ÷2.5

120 inches : 48 feet

              ÷2.5

answer: 48 feet

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The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh
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Answer:

The correct answer is:

The volume of the triangular prism is equal to the volume of the cylinder

Step-by-step explanation:

Given that there are two figures

1. A right triangular prism and

2. Right cylinder

Area of cross section of prism is equal to Area of cross section of cylinder.

Let this value be <em>A</em>.

Also given that Height of prism = Height of cylinder = <em>6</em>

Volume of a prism is given as:

V_{Prism} = \text{Area of cross section} \times Height

V_{Prism} = A \times 6 ........ (1)

Cross section of cylinder is a circle.

<em>Area of circle</em> is given as: \pi r^{2}

Area of cross section, A = \pi r^{2}

Volume of cylinder is given as:

V_{Cylinder} = \pi r^{2} h\\\Rightarrow V_{Cylinder} = A \times h\\\Rightarrow V_{Cylinder} = A \times 6 ...... (2)

From equations (1) and (2) we can see that

V_{Prism}=V_{Cylinder}

Hence, the correct answer is:

Volume of prism is equal to the volume of cylinder.

3 0
2 years ago
In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalizat
Viktor [21]

Answer:

Sample mean for solution 1:  19.27; sample mean for solution 2:  10.32

Step-by-step explanation:

To find the sample mean, find the sum of the data values and divide by the sample size.

For solution 1, the sum is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10; this gives us

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

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3 years ago
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6 0
3 years ago
Help please! anything will help thanks ya'll.!
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The cosine of A is (adjacent side)/(hypotenuse) = 55/73. Do the division, then find the angle whose cosine is that number. The whole thing takes maybe 6 or 7 seconds with your calculator. It's choice-B.
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3 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
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