Answer:
The values of a and b are a = 11 , b = 7
Step-by-step explanation:
* Lets explain how to solve the problem
* In the exponential functions we have some rules
1- In multiplication if they have same base we add the power
# Ex: b^m × b^n = b^(m + n) ⇒ b is the base , m and n are the powers
2- In division if they have same base we subtract the power
# Ex: b^m ÷ b^n = b^(m – n) ⇒ b is the base , m and n are the powers
3- If we have power over power we multiply them
# Ex: (b^m)^n = b^(mn) ⇒ b is the base , m and n are the powers
* Lets solve the problem
∵ The equation is 
⇒ (1)
- At first multiply the coefficients
∵ -4 × 5 = -20
- Multiply the base x
∵ 
- Multiply the base y
∵ 
∴ 
⇒ (2)
- By comparing (1) and (2)
∴ a = 11 and b = 7
* The values of a and b are a = 11 , b = 7
Given:
To find:
Select the true statements from the given options about the given value.
Solution:
We have,
It can be written as
![[\because \log(ab)=\log a+\log b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%28ab%29%3D%5Clog%20a%2B%5Clog%20b%5D)
Clearly, the value of x lies between 4 and 5. So, 
and 
.
Therefore, the correct options are C and D.
Answer:
a = -4
Step-by-step explanation:
Solve for a:
-7 (3 a - 1) = 91
Divide both sides of -7 (3 a - 1) = 91 by -7:
(-7 (3 a - 1))/(-7) = 91/(-7)
(-7)/(-7) = 1:
3 a - 1 = 91/(-7)
The gcd of 91 and -7 is 7, so 91/(-7) = (7×13)/(7 (-1)) = 7/7×13/(-1) = 13/(-1):
3 a - 1 = 13/(-1)
Multiply numerator and denominator of 13/(-1) by -1:
3 a - 1 = -13
Add 1 to both sides:
3 a + (1 - 1) = 1 - 13
1 - 1 = 0:
3 a = 1 - 13
1 - 13 = -12:
3 a = -12
Divide both sides of 3 a = -12 by 3:
(3 a)/3 = (-12)/3
3/3 = 1:
a = (-12)/3
The gcd of -12 and 3 is 3, so (-12)/3 = (3 (-4))/(3×1) = 3/3×-4 = -4:
Answer: a = -4
To solve this we have to work backwards.
start with -7 and add 12 to it to undo the first move
now take 5 and multiply by 5 to undo the last move
check our work:
Answer:
8 km
Step-by-step explanation:
im a genius in math so trust me
