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3 years ago

The public library has fewer than 4,000 books.

Mathematics

2 answers:

hichkok12 [17]3 years ago

7 0

Answer: The correct option is (A) b < 4000.

Step-by-step explanation: Given that the public library has fewer than 4,000 books.

We are to select the inequality that describes the number of books in the library.

The number of books in the library is represented by b.

According to the given information, the inequality hat describes the number of books in the library is given by

$b$

Thus, (A) is the correct option.

Dvinal [7]3 years ago

5 0

B<4,000 is the inequality because b is less than 4,000

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4 years ago

IS 6 THREE FOURTHS DIVIDED BY NINE DIVIDED BY 10 EQUAL TO 6 THREE FOURTHS DIVIDED BY NINE TENTHS

sergeinik [125]

Answer:

yes

Step-by-step explanation:

because 9 tenths is 9/10

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3 years ago

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In a manufactory, there are two types of spoilages. It is found that 5% of spoilages are due to transformer spoilage, 8% are due

jok3333 [9.3K]

Answer:

Step-by-step explanation:

Let us denote probability of spoilage as follows

Transformer spoilage = P( T ) ; line spoilage P ( L )

Both P ( T ∩ L ) .

Given

P( T ) = .05

P ( L ) = .08

P ( T ∩ L ) = .03

a )

For independent events

P ( T ∩ L ) = P( T ) x P ( L )

But .03 ≠ .05 x .08

So they are not independent of each other .

b )

i )

Probability of line spoilage given that there is transformer spoilage

P L/ T ) = P ( T ∩ L ) / P( T )

= .03 / .05

= 3 / 5 .

ii )

Probability of transformer spoilage but not line spoilage.

P( T ) - P ( T ∩ L )

.05 - .03

= .02

iii )Probability of transformer spoilage given that there is no line spoilage

[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )

= .02 / 1 - .08

= .02 / .92

= 1 / 49.

i v )

Neither transformer spoilage nor there is no line spoilage

= 1 - P ( T ∪ L )

1 - [ P( T ) + P ( L ) - P ( T ∩ L ]

= 1 - ( .05 + .08 - .03 )

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3 years ago

This app is so useless!

klio [65]

Answer:

lol ik people dont even come to answer the questions they just come for the points...

Step-by-step explanation:

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3 years ago

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kipiarov [429]

Answer:

8.49%

Step-by-step explanation:

x months

$f(x) =\frac{x^2+64}{2x}$ 1 ≤ x ≤ 12

minimum: $f'(x) = 0$

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$f(4\sqrt{2} ) = \frac{(4\sqrt{2})^2 +64}{2.4\sqrt{2} } = \frac{32+64}{8\sqrt{2} } = \frac{96}{8\sqrt{2} }=\frac{12}{\sqrt{2} } = 6\sqrt{2}$ ≅8.49%

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3 years ago