Weight=smallertotalweight+largertotalweight
smallertotalweight=weight times how many
largertotalweight=weight times how many
lets call them s and l
smaller and larger
650=50s+75l
and
550=100s+25l
simplfiy the m all by dividing by 5
130=10s+15l
110=20s+5l
divide by 5 again
26=2s+3l
22=4s+l
we can eliminate the s's
multiply first equatn by -2 and add to first
22=4s+l
<u>-52=-4s-6l +</u>
-30=0s-5l
-30=-5l
divide both sides by -5
6=l
input back
22=4s+l
22=4s+6
minus 6
16=4s
divide 4
4=s
each smaller model weighs 4 pounds
larger weighs 6 pounds
Answer: -22 you’re welcome
Answer:
15+ (B x 7)
Step-by-step explanation:
Answer:
YZ = 4
Step-by-step explanation:
△XZW is simliar to △ YZV
Then use ratios to find the missing side
8/x = 12/6
12x = 48
x = 4
Also good luck on IXL that suuuucccckkksss
Answer:
The answer to this is 5/6
Step-by-step explanation:
Use cross-multiply which cancels 8 out
now you are left with, 5/6
Hope this Helped!!!
~Shane