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Elza [17]
3 years ago
14

A purse is on sale for $146.47 after a 30% discount. What was the original price of the purse?

Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

190.41 is the original price

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The answer is 36° 


Hope that helps, Good luck! (:
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Help please it’s homework
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Answer:

10. 1/9

11. 1 1/6

12. 1/8

Step-by-step explanation:

10.

He spent 2/3 of 1/6 of the day.

In math, "of" means multiplication, so 2/3 of 1/6 means 2/3 * 1/6.

2/3 * 1/6 = 2/18 = 1/9

He spent 1/9 of the day adding mulch.

11.

He spent 2/3 of 1 3/4 hours.

In math, "of" means multiplication, so 2/3 of 1 3/4 means 2/3 * 1 3/4.

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He spent 1 1/6 hours working on the project.

12.

She planted 1/6 of 3/4 of the area.

In math, "of" means multiplication, so 1/6 of 3/4 means 1/6 * 3/4.

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She planted carrots in 1/8 of the garden.

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3 years ago
The diameter of a circle measures 17 mm. What is the measure of its radius ?
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the radius is 8.5 mm

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George, the ginger cat weighs 14 pounds. His pal, lgor weighs 6 pounds. How much more does george weigh than lgor
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Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past
blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

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(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0
3 years ago
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