Answer:
EF = 6
Step-by-step explanation:
Using the secant- secant power theorem, that is
GF × GE = GH × GS
4(4 + 2x) = 5(5 + x) ← distribute both sides
16 + 8x = 25 + 5x ( subtract 5x from both sides )
16 + 3x = 25 ( subtract 16 from both sides )
3x = 9 ( divide both sides by 3 )
x = 3
Then
EF = 2x = 2 × 3 = 6
In reflection, translation and rotations the pre image and the image are congruent and in dilation they are similar <span />
The equation of the quadratic function in standard form as required in the task content is; f(x) = -x² + 12x - 43.
<h3>Standard form equation of a quadratic function.</h3>
It follows from the task content that the standard form equation of the quadratic function is to.be determined.
Since the standard form equation can be derived from the vertex form equation as follows;
f(x) = a (x - h)² + k
f(x) = a (x - 6)² - 7
Hence, to find the value of a, Substitute x = 8 and f(x) = -11 so that we have;
-11 = a (8 - 6)² - 7
-11 = 4a - 7
4a = -4
a = -1.
Hence, the equation in vertex form is; f(x) = -1 (x -6)² - 7 and when expressed in standard form we have;
f(x) = -1(x² - 12x + 36) - 7
f(x) = -x² + 12x - 43
Therefore, the required equation in standard form is; f(x) = -x² + 12x - 43.
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Answer:
I believe the answer you are looking for is C-√57
Mark brainliest :)