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Dafna11 [192]
3 years ago
10

Exponent Laws - difference between product law and product raised to a power (with formula please)

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

Exponent laws:

1. Product law

x^{a}\times x^{b}\times x^{c}=x^{a+b+c}

In product law if bases are same then we add their respective powers.But if bases are different we can't add their powers.

x=base, a,b,c=exponent

If x=2 and a=3, b=5 , and c=10, then

2^{3}\times2^{5}\times2^{10}=2^{3+5+10}=2^{18}

2.Product raised to a power

1. [x^{a}]^{c}=x^{ac}

2. [x^{a}\times x^{b}]^{c}=[x^{a+b}]^{c}=x^{ac+bc}

If product is raised to a certain power , keeping the base same , we just multiply the powers.for example

[2^{3}]^{4}=2^{3\times4}=2^{12} and

[2^{3}\times3^{2}]^{2}=[2^{3}]^2 \times[3^{2}]^{2}=2^{6}\times3^{4}

[2^{3}\times2^{2}]^{2}=[2^{3+2}]^{2}=[2^{5}]^{2}=2^{10}



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kodGreya [7K]

Answer:

If we are working in a coordinate plane where the endpoints has the coordinates (x1,y1) and (x2,y2) then the midpoint coordinates is found by using the following formula:

midpoint=(x1+x22,y1+y22)

Step-by-step explanation:

5 0
3 years ago
Rewrite in the form . Then find q(x) and r(x).
gizmo_the_mogwai [7]

Answer:

q(x)= 2x+5

r(x)=6

b(x)=x+4

Step-by-step explanation:

I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).

First, we have to divide the polynomial  by x+4 and remember that is x times 2x.

By multiplying this we are going to get 2x^{2} + 8x and now we are doing separation of it and getting 2x^{2}  + 13x + 26 and getting 2x^{2}  + 13x + 26/ x + 4 = 2x^{2} +8x/x+4=5x+26/x+4=2x + 5x+26/x+4

Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.

5x+26/x+4 = 5x + 20/x+4 = 6/ x+4=5 + 6/x+4

Now when we can get more simplified we are having:

2x^{2} +13+26/x+4=2x + 5= 6/x+4

3 0
3 years ago
Find dy/dx using first principle<br>x+1/x​
JulsSmile [24]

Answer:

The derivative of the function is:

f'(x)=1-\frac{1}{x^{2}}

Step-by-step explanation:

The first principle is given by:

f'(x)=\frac{dy}{dx}=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

The function here is:

f(x)=x+\frac{1}{x}

Now, using the first principle we have:

f'(x)=lim_{h\rightarrow 0}\frac{(x+h)+\frac{1}{(x+h)}-x-\frac{1}{x}}{h}  

=lim_{h\rightarrow 0}\frac{h+\frac{1}{(x+h)}-\frac{1}{x}}{h}    

=lim_{h\rightarrow 0}\frac{h-\frac{h}{x(x+h)}}{h}    

=lim_{h\rightarrow 0}\frac{h(1-\frac{1}{x(x+h)})}{h}

=lim_{h\rightarrow 0}1-\frac{1}{x(x+h)}

=1-\frac{1}{x^{2}}

 

Therefore, the derivative of the function is:

f'(x)=1-\frac{1}{x^{2}}

I hope it helps you!  

 

6 0
2 years ago
Solve for X<br> 7x^2-2x^4+9
kati45 [8]

Answer:

9 − 2 4 + 9

Step-by-step explanation:

6 0
3 years ago
Adam is 2 years old. His sister lina is 1 year less than 3 times his age.write a numerical expression for linas age
Andre45 [30]

Answer:

Step-by-step explanation:

Let's take it part by part.

" lina is 1 year less than..."  So this means a value that we get some other way -1.  So let's call it x-1 for now.  The next part tells us how to get x.

"3 times his age"  so now we have 3y-1, where y is Adam's age.  We know adam's age though.

3*2 - 1

6-1

5

3 0
3 years ago
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