Simplify (7^5)^3 A. 7^15 B. 35^3 C. 7^8 D. (1/7)^3

PLEASE ANSWER CORRECTLY and show your work! I will give brainliest!

Alenkinab [10]

Answer: The new co-ordinates of A ( 2 ,-6)

Step-by-step explanation:

Type of transformation change to co-ordinate point

Vertical translation up 'd' units (x,y)→(x , y+d)

Vertical translation down 'd' units (x,y)→(x , y-d)

Horizontal translation right 'c' units (x,y)→(x+c , y)

Horizontal translation left 'c' units (x,y)→(x-c , y)

Reflection over x-axis (x,y) →(x , -y)

Reflection over y-axis (x,y) →(-x , y)

Given the original vertex A ( -2 ,3)

a) First reflection over x-axis ( -2 ,3) →(-2 , -3)

b) Vertical translation down '3' units so it changes (-2 , -3)→(-2 , -3-3)

(-2,-3)→(-2 ,-6)

and

c) The Horizontal translation right '4' units

now it changes ( -2 ,-6) → (-2+4,-6)→(2 ,-6)

Final answer:-

The new co-ordinates of A ( 2 ,-6)

3 0

3 years ago

A purse contains $1.15 in nickles and dimes and has 20 coins. How many nickles are in the purse?

lisov135 [29]

There are 23 nickles in her purse

4 0

3 years ago

Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)

vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

Two angles are said to be supplementary when they add up to 180°.

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

Two angles are said to be complementary when they add up to 90°.

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0

4 years ago

HELP ME ON THIS PLEASE!!!! SHOW WORK!!!!

Mumz [18]

Answer:

Step-by-step explanation:

1.

ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:

$\dfrac{AC}{AJ}=\dfrac{AB}{AK}$

We have:

AC = 1 + 4 = 5

AJ = 1

AB = 1 + x

AK = 1

Substitute:

$\dfrac{5}{1}=\dfrac{1+x}{1}$

$5=1+x$ subtract 1 from both sides

$4=x\to x=4$

2.

ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:

$\dfrac{VU}{VM}=\dfrac{VT}{VN}$

We hve:

VU = x + 8

VM = x

VT = 49

VN = 49 - 14 = 35

Substitute:

$\dfrac{x+8}{x}=\dfrac{49}{35}$ cross multiply

$35(x+8)=49x$ use the distributive property a(c + b) = ab + ac

$35x+280=49x$ subtract 35x from both sides

$280=14x$ divide both sides by 14

$20=x\to x=20$

3 0

3 years ago

Easy easy point answer the question

Gala2k [10]

Answer:

2 7/8

Step-by-step explanation:

4 0

3 years ago

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