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amid [387]
1 year ago
8

Simplify (7^5)^3 A. 7^15 B. 35^3 C. 7^8 D. (1/7)^3

Mathematics
1 answer:
Olegator [25]1 year ago
3 0

Answer:

7^15

Step-by-step explanation:

7^5^3 = 7^(5*3) = 7^15

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A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye
Svetlanka [38]

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

6 0
3 years ago
Factor out the greatest common factor.<br> 30t2u + 12tu2 + 24tu
Alexandra [31]
First you can combine 30tu^2 and 12tu^2 because they both have tu^2

So it would be 42tu^2 + 24tu

The answer is
6tu ( 7tu + 4 )



7 0
3 years ago
the cheese that ms.carter used to buy costs $6.00 per pound, but it's been marked up to 15%. suppose ms.carter buys 3.5 pounds o
kap26 [50]
Original price: 
6(3.5)
21
New Price:
1.15(21)
24.15

24.15-21
$3.15 more
5 0
2 years ago
Read 2 more answers
Bruce and his family arrived at the beach at 10:28 a.m. on Saturday morning. They left their house 12 hours and 20 minutes befor
nevsk [136]

Answer:

10:48 pm will be your answer

4 0
2 years ago
Could someone Help me please!
Aliun [14]
C = 2 pi r
C = 2 x 3.14 x 5 
C = 31.4 yd

A = pi r^2
A = 3.14 x 5^2
A = 3.14 x 25
A = 78.5 yd^2
4 0
2 years ago
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