Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is

Since there are n logs in the pile, so we get

Thus, the total number of logs in the pile is 6.
First you can combine 30tu^2 and 12tu^2 because they both have tu^2
So it would be 42tu^2 + 24tu
The answer is
6tu ( 7tu + 4 )
Original price:
6(3.5)
21
New Price:
1.15(21)
24.15
24.15-21
$3.15 more
C = 2 pi r
C = 2 x 3.14 x 5
C = 31.4 yd
A = pi r^2
A = 3.14 x 5^2
A = 3.14 x 25
A = 78.5 yd^2