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Rasek [7]
3 years ago
12

write an equation of the line with the same slope as the line given by 5x+2y=8 and as the same y-intercept as 3x-7y=10

Mathematics
2 answers:
Paladinen [302]3 years ago
5 0
The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
vampirchik [111]3 years ago
4 0
5x+2y=8\ \ \Rightarrow\ \ 2y=-5x+8\ \ \Rightarrow\ \l_1:\  y=- \frac{5}{2}x+8\\ \\ l_2:\ y=ax+b\ \ \ and\ \ \ l_2\ ||\ l_1\ \ \ \Leftrightarrow\ \ \ a=- \frac{5}{2} \\ \\l_2:\ y=- \frac{5}{2}x+b\\ \\3x-7y=10\ \ \ and\ \ \ x=0 \ \ \ \Rightarrow\ \ \ 3\cdot0-7y=10 \ \ \Rightarrow\ \ \ y=- \frac{10}{7}  \\ \\b=- \frac{10}{7}\ \ \ \Rightarrow\ \ \  l_2:\ y=- \frac{5}{2}x- \frac{10}{7}\\ \\ l_2:\  \frac{5}{2}x+y=- \frac{10}{7}\ \ /\cdot14\\ \\l_2:\ 35x+7y=-20
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An expirement consists of rolling two fair number cubes. What is the probability that the sum of the two numbers will be 4? Expr
ExtremeBDS [4]

Answer:

\dfrac{1}{12}

Step-by-step explanation:

Given:

Two fair number cubes i.e. two dice consisting the numbers 1, 2, 3, 4, 5, 6 on their faces and have equal probability of each number.

The dice are rolled.

To find:

Probability of getting the sum of two numbers as 4.

Solution:

First of all, let us have a look at the total possibilities when two dice are rolled:

([1][1], [1][2], [1][3], [1][4], [1][5], [1][6],

[2][1], [2][2], [2][3], [2][4], [2][5], [2][6],

[3][1], [3][2], [3][3], [3][4], [3][5], [3][6],

[4][1], [4][2], [4][3], [4][4], [4][5], [4][6],

[5][1], [5][2], [5][3], [5][4], [5][5], [5][6],

[6][1], [6][2], [6][3], [6][4], [6][5], [6][6])

These are total 36 possible outcomes.

For getting a sum as 4:

Possible number of favorable cases are 3 (as highlighted in BOLD in above)

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Required probability is:

\dfrac{3}{36} = \bold{\dfrac{1}{12}}

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and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

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b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

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We end up with the same integral as before except for the leading constant:

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c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

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