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Oduvanchick [21]
3 years ago
6

Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person,

there would be a 100% chance of contracting the disease if 2 contacts were made with the infected person?
Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer:

No it cannot be concluded.

Step-by-step explanation:

The probability of getting the disease in the first attempt is 50%

The probability of getting the disease in the second attempt is 50%

Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)

BUT

The probability of not  getting the disease in the first attempt is 50%

The probability of not getting the disease in the second attempt is 50%

Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)

Thus the probability of getting the disease in either of the 2 contacts is still 50%

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A water tank holds 944 gallons but is leaking at a rate of 5 gallons per week. A second water tank holds 1,180 gallons but is le
podryga [215]

Answer:

59

Step-by-step explanation:

The equation is

944 - 5x = 1180 - 9x

Notice what is being said. You start with 944 gallons and take off 5 per week

You also start with 1180 gallons and take on 9 per week.

You want to know when the two are equal. The second tank is larger, but it leaks more. That's what's going to bring about equality.

Add 9x to both sides

944 - 5x + 9x = 1180

944 + 4x = 1180                

Subtract 944 from both sides.

4x = 1180 - 944

4x = 236      

Divide by 4

x = 236/4

x = 59 weeks

8 0
3 years ago
How do you do this?<br>please help if possible!
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6w - 17b = w
6w - w = 17b
5w = 17b
(5/17)w = b

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7 0
3 years ago
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I am having trouble<br> 2(10-13x)=-34x+60
morpeh [17]
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(10 * 2 + -13x * 2) = -34x + 60
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Add '-20' to each side of the equation. 20 + -20 + 8x = 60 + -20
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7 0
3 years ago
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