One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
</span>
Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
</span>
D. 6 1/2
Just divide 13 by 2 and you will get 6.5 or 6 1/2
Answer:
Step-by-step explanation:
you do part a
Equation 1: 4x+y=2
Equation 2: 3x-3y=9
b
Divide equation 2 by 3
x-y=3
add y to both sides
x=3+y
Sbustitute this into equation 1
4(3+y)=2
12+4y+y=2
5y= -10
y= -2
Plug this into equation 1
4x-2=2
x=1
Part c.
Equation 1: 4x+y=2
Equation 2: 3x-3y=9
divide equation 2 by 3
x-y=3
add the two equations
(x-y)+(4x+y)=2+3
5x=5
x=1
Plug this into equation 1
4(1)+y=2
4+y=2
y= -2
For part a just create a table and graph it