Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.
Answer: |81-x|<5
Step-by-step explanation:
Given: Temperature of an enclosure for a pet corn snake should be an average of 81° F.
Temperature in the enclosure should not vary by more than 5° F.
Let x= Temperature in the enclosure
Then, difference between average and current temperature should less the 5.
i.e. |81-x|<5 (required absolute value equation )
hence, the absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure:
|81-x|<5
★ 100% of 15 = X


★ 20% of 15 = Y



<u>Answers</u> : X = 15 and Y = 3
Six hundred two thousand hundred seven.
Answer:
a)
Slope form y=2x+3
Standard form 2x-y=-3
b)
Slope y=3/5x-6
Standard 3x-5y=30
c)
slope y=-3/2x+9
standard 3x+2y=18
d)
slope y=-3x+0
standard = 3x+y=0
Step-by-step explanation:
a)
Slope form y=2x+3
Standard form 2x-y=-3
b)
Slope y=3/5x-6
Standard 3x-5y=30
c)
slope y=-3/2x+9
standard 3x+2y=18
d)
slope y=-3x+0
standard = 3x+y=0