eleven wins to one lose 11 to 1
(f+g)(x)=f(x)+g(x)=(2x-6)+(4x+7)=6x+1
(f-g)(x)=f(x)-g(x)=(2x-6)-(4x+7)=-2x-13
(fg)(x)=f(x)×g(x)=(2x-6)(4x+7)=8x^2-10x-42
(f+g)(-2)=f(-2)+g(-2)=(2(-2)-6)+(4(-2)+7)=-11
Answer:
10y + 20 -11 =139
10y = 130
y = 130 / 10
y = 13
Step-by-step explanation:
Now, check the picture below
the area of the cross-sections, is really the same area as the rectangular faces, so, just use those areas, since they're the same