<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
The solution to the problem about the possible values of x in the inequality is as follows:
4(x+15) >= 120
x+15 >= 30
<span>x >= 15
Therefore, there are </span><span>x >= 15 possibilities in the inequality.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
Right twice
Im honestly guessing
soz if utss wrong
Answer: Option C.
Step-by-step explanation:
Let as consider the complete question is same as question shown in the below figure.
In the figure m║n.
If a transversal line intersect two parallel lines then same sided interior angles are supplementary angles and their sum is 180 degrees.
Divide both sides by 4.
The value of x is 45 degrees.
Therefore, the correct option is C.
Answer:
$10.50
Step-by-step explanation:
3.50x3=10.50
(what table)
