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Oxana [17]
3 years ago
10

(6n-25) + (3n + 20) = 180

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

n = 185/9

Step-by-step explanation:

(6n-25) + (3n + 20) = 180

Combine like terms

9n -5 = 180

Add 5 to each side

9n - 5 +5 = 180+5

9n = 185

Divide each side by 9

9n/9 = 185/9

n = 185/9

Yuki888 [10]3 years ago
6 0
Answer: n= 20.5

Explanation: solve the equation by isolating the variable than dividing each side by other factors.
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Converting Mixed Numbers to Improper Fractions.
andrew11 [14]
Just multiply the denominator and the whole number then add the numerator

23/9
7/2
37/5
16/5
23/4
33/5

The answers are in order you put it in like 1-6

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6 0
3 years ago
Which situation is most likely to have a constant rate of change? A. Length of a bead necklace compared with the number of ident
Kipish [7]

Answer:

A. Length of a bead necklace compared with the number of identical beads

Step-by-step explanation:

Using identical beads in a necklace means that the length of the necklace will depend on the total number of identical beads in the necklace.

For each bead added, the length of the necklace will increase a given, constant, amount.  This is a constant rate of change.

5 0
3 years ago
Read 2 more answers
Steven works at the Pi Day food truck and he gets paid $9 per hour x. If 1 point
vitfil [10]
P(x) =9x +30

the tips are a flat rate so it’s a constant 30 while the 9 per hour is dependent on the hours worked which is why it is attached to x as a coefficient
8 0
3 years ago
Is 11/2 and 6/11 equivalent? Plz I need the help☹️
trapecia [35]

For this case we have the following fractions:

\frac {11} {2}\\\frac {6} {11}

We must rewrite the fractions, using the same denominator.

We have then:

We multiply the first fraction by 11 in the numerator and denominator:

\frac {11} {2} \frac {11} {11}

We multiply the second fraction by 2 in the numerator and denominator:

\frac {6} {11} \frac {2} {2}

Rewriting we have:

For the first fraction:

\frac {121} {22}

For the second fraction:

\frac {12} {22}

We note that:

\frac {121} {22}> \frac {12} {22}

Answer:

The fractions are not equivalent:

\frac {11} {2}> \frac {6} {11}

5 0
3 years ago
Question 5: How long will it take for 2 g of a sample of iodine-131, which has a half-life of about 8 days, to decay to 0.04 g?
Aleonysh [2.5K]

This problem can be represented through the following equation

A = A₀(1/2)^t/h

where

A----------->  is the amount of substance left after time t

A₀ ----------> is the original amount---------> 2 g

h------------->  is the half-life-----------> 8 days

for A=0.04 g

t=?

0.04 = 2(1/2)^t/8

0.02 = (1/2)^t/8

Take ln on both sides:

ln(0.02) = ln [(1/2)^t/8]

ln(0.02) = (t/8)(ln 1/2)

t = 8*ln(0.02)/ln(1/2)

t = 45.15 days

the answer is 45.15 days

4 0
3 years ago
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