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Lilit [14]
3 years ago
7

Evaluate the expression without using a calculator: log10^3x-2y

Mathematics
2 answers:
kykrilka [37]3 years ago
4 0

Answer:

\huge\boxed{\log10^{3x-2y}=3x-2y}

Step-by-step explanation:

\text{Use}\\\\(1)\log x=\log_{10}x\qquad(x>0)\\\\(2)\log_ab^n=n\log_ab\qquad(a>0;\ a\neq1;\ b>0)\\\\(3)\log_aa=1\qquad(a>0;\ a\neq1)\\\\\log10^{3x-2y}=\underbrace{(3x-2y)\log10}_{(2)}=\underbrace{(3x-2y)\log_{10}10}_{(1)}=\underbrace{(3x-2y)(1)}_{(3)}=3x-2y

Kruka [31]3 years ago
3 0

Answer:

3x-2y

Step-by-step explanation:

log10^(3x-2y)

We know the base is base 10 since it is not written

log10 10^(3x-2y)

The log10 10 cancels

3x-2y

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