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Minchanka [31]
3 years ago
5

Triangle ABC has vertices at A(-3,4)B(4,-2)C(8,3).The triangle is translated 4 units down and 3 units left . Which rule represen

ts the translation? After the translation, what are the coordinates of vertex C
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

A translation of 4 units down means subtract 4 from the y- coordinate of the original point and a translation of 3 units left means subtract 3 from the original x- coordinate, thus translation rule is

(x, y ) → (x - 3, y - 4 )

Thus

C(8, 3 ) → C'(8 - 3, 3 - 4 ) → C'(5, - 1 )

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The solution of two linear equations is (-2,2). One equations has a slope of 3. The slope of the other equation is the negative
Crank

The system of equations is:

3x-y=-8

x+3y=4

Step-by-step explanation:

Let the line 1 be: l_1

Let line 2 be: l_2

Both lines will pass through the same point (-2,2)

And

Given

m_1=3\\m_2=-\frac{1}{3}

<u>The slope intercept form for first line will be:</u>

y=m_1x+b

Putting values

y=3x+b

Putting the point in the equation

2=(-2)(3)+b\\2=-6+b\\b=2+6\\b=8

So, the equation is: y=3x+8

Converting the equation in standard form

y=3x+8

Subtracting y from both sides

0=3x-y+8

Subtracting 8 from both sides

3x-y=-8

<u>The second line's equation will be:</u>

y=m_2x+b

Putting slope

y=-\frac{1}{3}x+b

Putting the point

2=-\frac{1}{3}(-2)+b\\2=\frac{2}{3}+b\\b=2-\frac{2}{3}\\b=\frac{6-2}{3}\\b=\frac{4}{3}

The equation is:

y=-\frac{1}{3}x+\frac{4}{3}

Converting the equation in standard form

Multiplying whole equation by 3

3y=-x+4

Adding x on both sides

x+3y=4

Hence

The system of equations is:

3x-y=-8

x+3y=4

Keywords: Equation of line, Linear equation

Learn more about linear equation at:

  • brainly.com/question/2116906
  • brainly.com/question/2131336

#LearnwithBrainly

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