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yKpoI14uk [10]
4 years ago
14

Javier is comparing costs of two cars. Car A costs $130 per month for insurance and $0.10 per mile to run. Car B costs $108 per

month for insurance and $0.15 per mile to run. He defines x as the number of miles driven each month and y as the total cost to run the car. Which set of equations can be used to find the number of miles Javier would need to drive to make the costs equal?
Mathematics
2 answers:
Pavlova-9 [17]4 years ago
5 0

Answer:

Let 'x' be the number of miles driven each month

Let 'y' be the total cost to run the car

Car A costs $130 per month for insurance and $0.10 per mile to run.

Equation becomes: 130+0.10x

Car B costs $108 per month for insurance and $0.15 per mile to run.

Equation becomes: 108+0.15x

Now, we will make these equations equal to make the costs equal.

130+0.10x =  108+0.15x

nikklg [1K]4 years ago
3 0
The answer is 130 + .10m = 108 + .15m
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7 0
3 years ago
Need help with full work quick
vekshin1

Answer:

Step-by-step explanation:

36x^3 - 81x

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3 years ago
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max2010maxim [7]
The answer is y=2/12
3 0
3 years ago
Solve the system of linear equations by graphing. y = –5/2 x – 7 x + 2y = 4 What is the solution to the system of linear equatio
Anestetic [448]

Keywords

system; linear equations; graphing; solution

we have

y=-\frac{5}{2}x-7 -------> equation A

x+2y=4

x=4-2y ----> equation B

The <u>system</u> of <u>linear equations</u> is composed of equation A and equation B

Substitute the equation B in equation A

y=-\frac{5}{2}[4-2y]-7

y=-10+5y-7

4y=17

y=17/4=4.25

Find the value of x

x=4-2[17/4]=-4.5

The<u> solution</u> is the point (-4.5,4.25)

Using a <u>graphing</u> tool

see the attached figure

therefore

the answer is the option A

(-4.5,4.25)


4 0
3 years ago
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MakcuM [25]

Answer:

22.916666666 The six is repeated

Step-by-step explanation:

10/12=8.3333333 and 8.3333333*27.5=22.916666666 repeated

4 0
3 years ago
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