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Leviafan [203]
3 years ago
14

pls help me giving brainless. find all angle measures. Assume each truss is symmetric. All of the roofs have a total top peak an

gle of 120 degrees​

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

Pls mark me branliest

Download pdf
Molodets [167]3 years ago
5 0

Answer:

I hate to do and take the points but so we just got to find the angles?

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b,c,e

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Consider the case of a triangle with sides 5, 12, and the angle between them 90°.
Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c²  =  a²  +  b²

c²  =  (5)²  +  (12)²      ⇒  c²  = 25 + 144    ⇒ c²  =  169    ⇒  c  = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13    sin ∠α = 0.3846    ⇒      arcsin (0.3846 )   α  = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13    sinβ = 0.9230  arcsin(0.9230)   β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c²  = a² + b² - 2*a*b*cos90⁰   (law of cosines ) but cos 90⁰ = 0

then c²  = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c²  = a²  +  b²  - 2*5*13*cos α

169 = 25  +  144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not  apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c²  =  a²  +  b²  - 2*a*b*cos∠90°    cos ∠ 90°  = 0

Then     c²  =  a²  +  b²

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Answer:

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Step-by-step explanation:

Because a proportional relationship is one where x is proportional (equal) to y, and Graph A does not fall into that category, and Graph B does, the answer should be B.

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