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Feliz [49]
2 years ago
15

Hello!! Plz ans with explanation.. Plz!! I need it ASAP!!! PLZ TYSMFaaast!!

Mathematics
1 answer:
jonny [76]2 years ago
7 0

Answer:

1/4

1/2

3/4

Step-by-step explanation:

<u>Given</u><u>:</u>

Types of colors in the spinner

Yellow 1

Red 2

Blue 1

Total:4

Successful outcome of Yellow:1

Successful outcome of Red:2

Successful outcome of Blue:1

<u>Required</u><u>:</u>

Probability of the

  • blue sector
  • red sector
  • not on yellow sector

<u>Formula</u><u>:</u>

Probability= successful outcome ÷ possible outcome

<u>Solution</u><u> </u>

  • Blue sector

Probability=1 ÷ 4

  • Red sector

Probability= 2÷4

  • not on yellow sector

Probability= 3÷4

Hope this helps ;) ❤❤❤

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Christine has a bag of candy that contains 20 red pieces, 10 green pieces, 15 blue pieces, 25 brown pieces, and 10 orange pieces
andrew-mc [135]

Answer:

1/8

Step-by-step explanation:

20 + 10 + 25 + 15 + 10 =  80

10 / 80 = 1/8

4 0
1 year ago
Which translation will change figure ABCD to figure A prime B’C’D’?
levacccp [35]

Answer:

gods plan by drake

Step-by-step explanation:

3 0
2 years ago
If the range of the function f(x) = 4x – 3 is {11.4, 15, 17, 29}, what is its domain?
malfutka [58]
The range of the function is the y-component or the ordinate of the sets of points. The domain of the function meanwhile is the x-component ot the abscissa of the sets of points. In this case, we have the function <span>f(x) = 4x – 3 and given each y, we get the x. Subsituting each y to the function we get the domain equal to {3.535, 4.5, 5, 8}.</span>
5 0
3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

5 0
2 years ago
3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!
Nezavi [6.7K]
\text{Volume}=129.87cm^3

Explanation

Step 1

the density of an object is given by:

\text{density}=\text{ }\frac{mass}{\text{volume}}

Step 2

let

\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\  \end{gathered}

Step 3

replace,

\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\  \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}

I hope this helps you

5 0
1 year ago
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