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Stels [109]
3 years ago
8

In a class, 60% of the students are girls. There are 18 girls in the class. How many boys are in the class? How many students ar

e in the class?
Mathematics
2 answers:
seraphim [82]3 years ago
8 0
Percentage of students that are girls in the class = 60%
Number of girls in the class = 18
Let us assume the total number of students in the class = x
Then
60% * x = 18
(60/100) * x = 18
6x/10 = 18
6x = 18 * 10
6x = 180
x = 180/6
   = 30
So the total number of students in the class is 30.
Number of boys in the class = 30 - 18
                                               = 12
So there are 12 boys in the class. I hope the procedure is simple enough for you to understand.
sattari [20]3 years ago
7 0
60% are girls, there are 18 girls in the class. How many boys?

This is quite easy to understand. 

6x/10 = 18
6x/10 *10 = 18*10 
6x = 180
x = 30

Now, thats the total, subtract by the girls. 
30-18 = 12

Answer: 12

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2 years ago
2x+y=-9<br> -3x+11=y whathe is the answer
insens350 [35]
[ 2x + y = -9 ] x -3
[- 3x +11= y ] x 2

-6x -3y = 27
-6x + 22 = 2y

-6x +27 = 3y
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5 = y

-6x -3x5 = 27
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answer

x = -7
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8 0
3 years ago
Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a
LekaFEV [45]
To make this a little clearer, let's give the pairs of inequalities the same denominator:

<span>Question 1: 
</span>\frac{11}{15} ? \frac{5}{7}
First, apply the common denominator to the first fraction:
(\frac{11}{15})7 \\  \frac{11}{15} *  \frac{7}{7}  \\  \frac{11*7}{15*7}  \\  \frac{77}{105}
Do the same for the second:15( \frac{5}{7}) \\  \frac{5}{7}* \frac{15}{15} \\  \frac{5*15}{7*15}  \\  \frac{75}{105}
Nest, compare the two fractions:
\frac{77}{105} \ \textgreater \   \frac{75}{105}
Therefore:
\frac{11}{15} > \frac{5}{7}
<span>
Question Two:</span>
\frac{5}{9} ? \frac{7}{13}
Apply the common denominator to fraction one:
13( \frac{5}{9}) \\  \frac{5}{9} * \frac{13}{13}  \\  \frac{5*13}{9*13}  \\  \frac{65}{117}
Fraction two:
9(\frac{7}{13}) \\  \frac{7}{13} *  \frac{9}{9}  \\  \frac{7*9}{13*9}  \\  \frac{63}{117}
Evaluate:
\frac{65}{117} > \frac{63}{117}
Therefore:
<span>\frac{5}{9} > \frac{7}{13}
</span>
Hope this helps!
5 0
3 years ago
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Is it 4 times x or 4 to the power of x, if the first one then, 8x-24x. if the second then 8^-6x
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