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Stels [109]
3 years ago
8

In a class, 60% of the students are girls. There are 18 girls in the class. How many boys are in the class? How many students ar

e in the class?
Mathematics
2 answers:
seraphim [82]3 years ago
8 0
Percentage of students that are girls in the class = 60%
Number of girls in the class = 18
Let us assume the total number of students in the class = x
Then
60% * x = 18
(60/100) * x = 18
6x/10 = 18
6x = 18 * 10
6x = 180
x = 180/6
   = 30
So the total number of students in the class is 30.
Number of boys in the class = 30 - 18
                                               = 12
So there are 12 boys in the class. I hope the procedure is simple enough for you to understand.
sattari [20]3 years ago
7 0
60% are girls, there are 18 girls in the class. How many boys?

This is quite easy to understand. 

6x/10 = 18
6x/10 *10 = 18*10 
6x = 180
x = 30

Now, thats the total, subtract by the girls. 
30-18 = 12

Answer: 12

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Add the following fractions. See the image below
LenKa [72]

Answer:

\dfrac{19}{840}

Step-by-step explanation:

The given fraction is:

\dfrac{1}{168}+\dfrac{3}{180}

We need to solve it.

The LCM of 168 and 180 is 2520.

So,

\dfrac{1}{168}+\dfrac{3}{180}=\dfrac{15+3\cdot14}{2520}\\\\=\dfrac{19}{840}

So, the required answer is equal to \dfrac{19}{840}.

3 0
2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Please help me due at 12:50. Please please please, I love you . Don’t ignore this please.
bearhunter [10]

Answer:

9/10

Step-by-step explanation:

4/10 + 2/10 + 3/10 = 9/10

4 + 2 + 3 = 9

8 0
3 years ago
A student solved this problem and said the answer is 1 10  quart. Lila used 72 5  quarts of paint to paint her room. Renee used
MAXImum [283]

Answer:

b

Step-by-step explanation:

The right answer for the question that is being asked and shown above is that: "B.No, the answer is not reasonable. It should be about 13 quarts."A student solved this problem and said the answer is quart. Lila used quarts of paint to paint her room. Renee used quarts to paint her room. Lila use than Renee No, the answer is not reasonable. It should be about 13 quarts.

3 0
3 years ago
Read 2 more answers
What is 0.68 written as a slimplifed fraction
netineya [11]
0.68 = 68/100

68/100 simplest form is 17/25

hope this helps
5 0
3 years ago
Read 2 more answers
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