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Stels [109]
3 years ago
8

In a class, 60% of the students are girls. There are 18 girls in the class. How many boys are in the class? How many students ar

e in the class?
Mathematics
2 answers:
seraphim [82]3 years ago
8 0
Percentage of students that are girls in the class = 60%
Number of girls in the class = 18
Let us assume the total number of students in the class = x
Then
60% * x = 18
(60/100) * x = 18
6x/10 = 18
6x = 18 * 10
6x = 180
x = 180/6
   = 30
So the total number of students in the class is 30.
Number of boys in the class = 30 - 18
                                               = 12
So there are 12 boys in the class. I hope the procedure is simple enough for you to understand.
sattari [20]3 years ago
7 0
60% are girls, there are 18 girls in the class. How many boys?

This is quite easy to understand. 

6x/10 = 18
6x/10 *10 = 18*10 
6x = 180
x = 30

Now, thats the total, subtract by the girls. 
30-18 = 12

Answer: 12

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tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

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We want to determine the time(s) when the ball is 10 feet in the air.

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16x^2-64x+5=0

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\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

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\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

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\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

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\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

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2 years ago
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3 years ago
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igomit [66]
Hey there!

To solve this system of equations, you will need to get one of the terms in both equations to cancel out to zero. If there isn't a term that you can cancel out, you can multiply either or both equations to make that term. There's no wrong way to do this, just as long as you make sure that you double check whether your should add or subtract. This is easier shown than explained, so refer below:

<span>  x + y = +1
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</span>–1(x + y = +1)
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Hope this helped you out! :-)
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