What statement is true regarding the value of the digit in the tenths place of decimal 19.993

1 answer:

8 0

<span>The digit in the tenths place for the number "19.993" is "9". This represents the value of nine tenths or .9. In this value the tenths spot is the middle digit of the number and is surrounded by two other "9" values including a "9" in the hundredths value.</span>

You might be interested in

Kara earned $136.75 last week working 16 hours. She earned $10.50 per hour at the fast food restaurant and $4.25 per hour helpin

Evgesh-ka [11]

Answer:

ANSWER: she worked 11 hours at the fast food restaurant and 5 hours helping her aunt

Step-by-step explanation:

First we are going to try to find how many hours she worked on the fast food restaurant so you multiply 4.25 time 16 and x

10.50x + 4.25(16-x) =136.75

10.50x + 68 - 4.25x= 136.75

Then, you subtract 68 from both sides and subtract 4.25x from 10.50x

6.25x=68.75

Divide

X=11 that is how many hours she worked at the FAST FOOD RESTAURANT

Then 16-11 and that gives us how many hours she helped her aunt.

3 0

3 years ago

10v2 + 50

Svetach [21]

Answer:

what is the question? probably describe the polynomial. okay. the polynomial 10v^2 + 50 is a quadratic (it is to the 2nd power) and a binomial (has 2 terms).

7 0

3 years ago

Find the side length of X

7nadin3 [17]

Answer:

7√3

Step-by-step explanation:

We can use pythagoreans theorem to solve this

Since, we know one side, and the hypotenuse, we can solve for the other side.

Pythagoreans theorem: a²+b²=c²

Where a and b are two sides, and c is the hypotenuse (the side opposite of the right angle)

In this triangle, 7 is the side, and 14 is the hypotenuse.

I will plug in the values into pythagoreans theorem, and then simplify:

$a^{2}+b^{2} =c^{2} \\\\7^{2} +x^{2} =14^{2} \\\\49+x^{2} =196\\\\x^{2} =147\\\\x=\sqrt{147} \\\\x=\sqrt{49*3 }\\\\ x=\sqrt{7^{2} *3 }\\\\x=7\sqrt{3}$