We are given
P = <span>$1,945.61
r = 11.2%
Amin = $156
A = $300
First, we convert the interest to effective monthly terms
i = 11.2%/12 = 0.933%
After one month, the interest saved by paying more than the minimum is
</span>(0.00933) (300 - 156) = $1.35
Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
We are given a line with the following data:
r-value = 0.657 (r)
standard deviation of x-coordinates = 2.445 (Sx)
standard deviation of y-coordinates = 9.902 (Sy)
We are asked to find the slope of the line up to 3 decimal places.
To find the slope of the line, based on the data that we have, we can use this formula:
slope, b = r * (Sy / Sx)
substitute the values to the formula:
b = 0.657 * ( 9.902 / 2.445 )
Solve for the b.
Therefore, the slope of the line is
b = 2.66078, round off to three decimal places:
b = 2.661 is the slope of the line.
Answer:
more than 1100
Step-by-step explanation:
The contribution margin for each package sold is ...
$6.50 -3.00 = $3.50
The number of packages that must be sold to cover fixed costs is ...
3.50n > 3850
n > 1100 . . . . . . . divide by 3.50
The company will generate a profit if more than 1100 packages are produced and sold each week.
_____
<em>Additional comment</em>
If exactly 1100 packages are sold, then costs are covered, but profit is 0. In order for profit to be positive, more than 1100 packages must be sold.
Bring it to the form ax + by = c, where a is positive, and there are no fractions in the equation.
Here, we need to add 2/5x to both sides:
2/5x + y = 0
Then multiply everything by 5 to get rid of the fraction
2x + 5y = 0 <==
