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enot [183]
3 years ago
11

-5=6m-1 solve for m

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0

Answer:

m= -2/3 or -0.6

Step-by-step explanation:

6m-1= -5+1

6m= -4/-6

m= - 2/3 or -0.6  

Pachacha [2.7K]3 years ago
7 0

Answer:

m = -2/3

Step-by-step explanation:

-5 = 6m-1

Rewrite

6m - 1 = -5

Add 1 to both sides

6m = -4

Divide both sides by 6

m = -4/6

Simplifying

m = -2/3

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A coordinate map of the local grocery store is shown below. Ice cream is located at the point (-8,0)(−8,0)left parenthesis, minu
Alona [7]

Answer:

Step-by-step explanation:

If on the coordinate map, ice cream is located at the point (-8,0) and sprinkles are located at the point (-8,6), we can find the distance between the coordinate points using the formula;

D = √(x2-x1)²+(y2-y1)²

Given

x1 = -8, y1 = 0, x2 = -8 and y2 = 6

Substitute

D = √(x2-x1)²+(y2-y1)²

D = √(-8-(-8))²+(6-0)²

D = √0²+6²

D = √36

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Hence the distance between the coordinate points is 6units

7 0
3 years ago
PLEASE SOMEONE HELP ME
Julli [10]

Answer:

The answer is 5 times

Step-by-step explanation:

First, we need to read the change in price in 2000 and 2007, from the graph.

So, the change in price in 2000 was $0.14 and in 2007 it was $0.71.

Now, we do the same thing we always do when comparing two values - we divide them. So:

0.71 / 0.14 = 5.07

Of course, we could multiply these values with 100, in order to avoid decimal numbers. Then we would get:

71 / 14 = 5.07

We could also divide this in the form of fractions:

71/100 / 14/100 = 5.07

There are several ways we could divide rational numbers, but the result will always be the same.

Change in price in 2007 was around 5 times greater than the change in 2000.

I hope this helps!!;-)

6 0
3 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
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