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arlik [135]
4 years ago
13

I neeed help please I dont know what to do

Mathematics
1 answer:
torisob [31]4 years ago
6 0

Answer:

y12/5

Step-by-step explanation:

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A large box of jelly beans weighs 96.58 lb the jelly beans are evenly divided into 22 bags what is the weight in pounds of the j
Vadim26 [7]

Answer:

The weight in each bag is 4.39lb.

Step-by-step explanation:

To solve this, you simply need to divide 96.58 by 22. The reason you do this is so that way you can divide all of the weight into 22 bags.

96.58 ÷ 22 = 4.39

This means that the weight in each bag is 4.39lb.

4 0
3 years ago
Help me please ❤️<br> Thank you
anyanavicka [17]

Answer:

I think it would be finding the quantity in each group.

Step-by-step explanation:

Because there would be more than 1 group. there is only one group. so you are trying to find the number of hours each person in the group will get.

i think that is right sorry if not.

5 0
3 years ago
Read 2 more answers
Find two z values so that the middle 65% of the area is bounded by them
Elena-2011 [213]

Answer: Firstly in this question, we need to solve for

α

which is the part of the distribution of which we not looking for.

we can do this with the sum:

α

=

1

−

0.76

=

0.24

as

0.76

=

76

%

we also know that our Standard Normal Distribution is symmetric, so we must divide that

α

to be split on either side of our distribution. so we solve for:

α

2

=

0.24

2

=

0.12

then we find a correlating

z

-score for the value

0.12

and we get that

−

z

=

−

1.175

and

z

=

1.175

This becomes easier to understand when visualized, so observe how we do this sum.

Step-by-step explanation:

4 0
2 years ago
Identify the polynomial written in ascending order. 8x3+ 2x2− 6x − 11 2x2− 11 + 8x3− 6x −6x + 8x3− 11 + 2x2 −11 − 6x + 2x2+ 8x3
Delvig [45]
Ascending order...smallest to largest

-11 - 6x + 2x^2 + 8x^3 <==
5 0
3 years ago
Read 2 more answers
Each time a component is tested the trial is a success (S) or failure (F). Suppose the component is tested repeatedly until a su
babymother [125]

Answer:

(a)\ \{SSS\}

(b)\ \{FSSS\}

(c)\ \{FFSSS, SFSSS\}

(d)\ \{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

(e)\ \{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

Step-by-step explanation:

Given

S\to Success

F\to Failure

n \to 3 Consecutive trials until S happens

Y \to Number of trials

For every possible outcome, the last 3 must be SSS. So, we have:

(a)\ Y = 3

The only possibility here is: \{SSS\}

because 3 trials implies that all outcomes must be S.

(b)\ Y = 4

The only possibility here is:

\{FSSS\}

because 4 trials implies that the first outcome must be F

 

(c)\ Y = 5

The possibilities are:

\{FFSSS, SFSSS\}

because 5 trials implies that the first and the second outcomes must be FS or SF.

(d)\ Y = 6

The possibilities are:

\{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

because 6 trials implies that the first three outcomes are: FFF, SSF and SFF

(e)\ Y = 7

The possibilities are:

\{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

because 7 trials implies that the first three outcomes are: FFFF, FSSF and SSFF and FFSF (similar to (e))

4 0
3 years ago
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