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4 years ago

How to find the value of X it's really confusing

Mathematics

2 answers:

Nastasia [14]4 years ago

8 0

(4 + 2(8x + 11) / 2 - 12 = 17...distribute through the parenthesis
(4 + 16x + 22) / 2 - 12 = 17 ...add 12 to both sides
( 16x + 26) / 2 = 17 + 12
(16x + 26) / 2 = 29 ...multiply both sides by 2
16x + 26 = 29 * 2
16x + 26 = 58 ...subtract 26 from both sides
16x = 58 - 26
16x = 32...divide both sides by 16
x = 32/16
x = 2 <==

Dovator [93]4 years ago

5 0

I believe the answer to your problem is x=1.25
You will want to get rid of the fraction so you multiply both sides of the equation by 2 and so you'd get
4+2(8x+11)-12=34 then you distribute
4+16x+22-12=34 then combine like terms

16x+14=34 and then move over 14
16x=20and then divide and isolate x
x=1.25

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Hdc produces microcomputer hard drives at four different production facilities (f1, f2, f3, and f4) hard drive production at f1,

OLEGan [10]

Let $D$ denote the event that an HD is defective, and $F_i$ the event that a particular HD was produced at facility $i$ .

You are asked to compute

$\mathbb P(F_2\mid D)$
$\mathbb P(F_4\mid D)$
$\mathbb P(D^C)$

From the definition of conditional probabilities, the first two will require that you first find $\mathbb P(D)$ . Once you have this, part (c) is trivial.

I'll demonstrate the computation for part (a). Part (b) is nearly identical.

(a)
$\mathbb P(F_2\mid D)=\dfrac{\mathbb P(F_2\cap D)}{\mathbb P(D)}$

Presumably, the facility responsible for producing a given HD is independent of whether the HD is defective or not, so $\mathbb P(F_2\cap D)=\mathbb P(F_2)\mathbb P(D)=0.20\times0.015$ .

Use the law of total probability to determine the value of the denominator:

$\mathbb P(D)=\mathbb P(D\mid F_1)+\mathbb P(D\mid F_2)+\mathbb P(D\mid F_3)+\mathbb P(D\mid F_4)$

We know each of the component probabilities because they are given explicitly: 0.015, 0.02, 0.01, and 0.03, respectively. So

$\mathbb P(D)=0.015+0.02+0.01+0.03=0.075$

and thus

$\mathbb P(F_2\mid D)=\dfrac{0.2\times0.015}{0.075}=0.04$

(b) Similarly,
$\mathbb P(F_4\mid D)=\dfrac{0.4\times0.03}{0.075}=0.16$

(c)
$\mathbb P(D^C)=1-\mathbb P(D)=0.925$

6 0

4 years ago

the volume V of a right circular cylinder of height 3 feet and radius r feet is V=V(r)=3(pi)(r^2). find the instantaneous rate o

Aleksandr-060686 [28]

When I see the words "instantaneous rate of change", I have to assume that you're in some stage of pre-calculus in your math class.

The instantaneous rate of change of a function is just its first derivative.

We have the function

V(r) = 3 π r²

and we need its first derivative with respect to ' r '. That shouldn't be
too hard, because the ' 3 π ' is nothing but constants.

Watch me while I do it slowly for you:

-- The derivative of ' r² ' with respect to ' r ' is ' 2r '.

-- The derivative of V(r) with respect to ' r ' is (3 π) times the derivative of ' r² '.

-- The derivative of V(r) with respect to ' r ' is (3 π) times (2r) = <u>6 π r</u> .

The value of the derivative when r=3 is (6 π 3) = 18π = about <em>56.5 feet³/foot .</em>

3 0

3 years ago

What is the value of x?

coldgirl [10]

ANSWER

58°

EXPLANATION

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$51 \degree = \frac{1}{2} (160 - x)$

Multiply through by 2

This implies that

$2 \times 51 \degree =2 \times \frac{1}{2} (160 - x)$

We simplify to get:

$102 \degree =160 - x$

Solve for x.

$102 \degree - 160 \degree =- x$

$- 58 \degree =- x$

$58 \degree =x$

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3 years ago

1,329.8 to 1 decimal place

rjkz [21]

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Step-by-step explanation:

7 0

4 years ago

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kogti [31]

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