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NikAS [45]
3 years ago
12

Plz help its due tonight!!!!

Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

Domain is (infinity, infinity) so it would hit every single number of x. The range which is y would be greater than or equal to -3. Range starts at -3 and hits every number above that.

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Jamie owns 150 baseball cards. Mason owns 96 baseball cards. What the number of Mason's cards written as a percent of Jamie's ca
Marina CMI [18]

Answer:

64%

95/150 Or 64%

7 0
3 years ago
Read 2 more answers
For the following right triangle, find the side length x.​
never [62]

Answer:

x = 10

Explanation:

Using Pythagoras Theorem:

  • a² + b² = c²

Solve:

8² + 6² = x²

x² = 64 + 36

x² = 100

x = √100

x = 10

8 0
2 years ago
Read 2 more answers
A rectangular gasoline tank can hold 45.0 kg of gasoline when full. what is the depth of the tank if it is 0.450 m wide by 0.900
garri49 [273]
The answer is 0.154 m

Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒   V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³

Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625  / 0.405
d = 0.154 m
7 0
3 years ago
Which of these is correct step in constructing congruent angles?
lapo4ka [179]
Is something missing
???????????????????//

6 0
3 years ago
What can you say about the y-values of the two functions f(x)=-5^x +2 and g(x)=-5x^2+2?
Kryger [21]

Answer:

B) The maximum y-value of f(x) approaches 2

C) g(x) has the largest possible y-value

Step-by-step explanation:

f(x)=-5^x+2

f(x) is an exponential function.

Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞

Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→

Lim x→ -∞ f(x) = 2

Then the maximun y-value of f(x) approaches 2


g(x)=-5x^2+2

g(x) is a quadratic function. The graph is a parabola

g(x)=ax^2+bx+c

a=-5<0, the parabola opens downward and has a maximum value at

x=-b/(2a)

b=0

c=2

x=-0/2(-5)

x=0/10

x=0

The maximum value is at x=0:

g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2

The maximum value of g(x) is 2

7 0
4 years ago
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