Plz help its due tonight!!!!

Mathematics

1 answer:

Natalka [10]3 years ago

8 0

Answer:

Domain is (infinity, infinity) so it would hit every single number of x. The range which is y would be greater than or equal to -3. Range starts at -3 and hits every number above that.

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Solve the system of linear equations using any method 6x+6y=-6, 5x+y=-13

Sergio [31]

Answer:

x=-3

y=2

Step-by-step explanation:

To solve this problem you can use the elimination method:

- Multiply the second equation by -6:

$(-6)5x+y=-13\\-30x-6y=78$

- Add both equations:

$6x+6y=-6\\-30x-6y=78\\-------\\-24x=72\\x=-3$

- Substitute the value of x into one of the original equations and solve for y:

$6(-3)+6y=-6\\-18+6y=-6\\6y=12\\y=2$

8 0

3 years ago

Read 2 more answers

The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co

FrozenT [24]

Let $Y_i$ denote the number of packages brought by customer $i$ . If, for instance, $X=2$ customers are in line, then the total number of packages is $Y=Y_1+Y_2$ , and

$P(Y=y)=P(Y_1=y_1,Y_2=y_2)=P(Y_1=y_1)P(Y_2=y_2)$

since the number of packages brought by any customer is independent from the number of packages brought by any other.

a. $P(X=3,Y=3)$ is the probability that a total of 3 packages are waiting to get wrapped from among a total of 3 customers. This means each customer must have exactly one package. So

$P(X=3,Y=3)=P(X=3)P(Y=3)^3\approx0.0416$

b. $P(X=4,Y=11)$ is the probability that a total of 11 packages are brought by 4 customers. The only way for there to be 11 packages is if 3 customers bring 3 packages and the last 1 brings 2. There are $\dbinom43=4$ ways this can happen, so